At a particular temperature, N 20 5 decomposes according to a first-order rate law with a half-life of 3.0 s. If the initial concentration of N 20 5 is 1.0 x 10 16 molecules/cm 3 after 11.5 s? what will be the concentration in molecules/cm O a. 1.0 × 1016 O b.2.3 × 10-1 O. 7.0× 1014 O d. 3.4 x 101 O e.2,0 × 1014
At a particular temperature, N 20 5 decomposes according to a first-order rate law with a half-life of 3.0 s. If the initial concentration of N 20 5 is 1.0 x 10 16 molecules/cm 3 after 11.5 s? what will be the concentration in molecules/cm O a. 1.0 × 1016 O b.2.3 × 10-1 O. 7.0× 1014 O d. 3.4 x 101 O e.2,0 × 1014
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![At a particular temperature, N 20 5 decomposes according to a first-order rate law with a half-life of 3.0 s. If the initial concentration ofN 20 5 is 1.0
х 10
16
molecules/cm
what will be the concentration in molecules/cm
3
after 11.5 s?
O a. 1.0 × 1016
O b.2.3 × 10-1
O. 7.0× 1014
O d. 3.4 x 101
O e. 2,0 × 1014](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3769e0db-2090-4c1a-8196-a1c6a28973b6%2Fcf505d74-46fd-4e56-8181-8d00eae65ebb%2Fp4i5cmt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:At a particular temperature, N 20 5 decomposes according to a first-order rate law with a half-life of 3.0 s. If the initial concentration ofN 20 5 is 1.0
х 10
16
molecules/cm
what will be the concentration in molecules/cm
3
after 11.5 s?
O a. 1.0 × 1016
O b.2.3 × 10-1
O. 7.0× 1014
O d. 3.4 x 101
O e. 2,0 × 1014
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