At a particular temperature a 2.00-L flask at equilibrium contains 5.10 x 10-4 moles of N₂, 2.50 x 10-5 moles of 02 and 2.00 x 10-2 moles of N₂O. Calculate K at this temperature for the reaction 2N₂ (g) + O₂(g) ⇒ 2N₂O(g) I K= If [N₂] = 2.00 × 10-4 M, [N₂O] = 0.200 M, and [0₂] = 0.00813 M, does this represent a system at equilibrium? Submit Answer 6 item attempts remaining Try Another Version
At a particular temperature a 2.00-L flask at equilibrium contains 5.10 x 10-4 moles of N₂, 2.50 x 10-5 moles of 02 and 2.00 x 10-2 moles of N₂O. Calculate K at this temperature for the reaction 2N₂ (g) + O₂(g) ⇒ 2N₂O(g) I K= If [N₂] = 2.00 × 10-4 M, [N₂O] = 0.200 M, and [0₂] = 0.00813 M, does this represent a system at equilibrium? Submit Answer 6 item attempts remaining Try Another Version
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium Calculation Exercise**
At a particular temperature, a 2.00-L flask at equilibrium contains:
- \(5.10 \times 10^{-4}\) moles of \(N_2\)
- \(2.50 \times 10^{-5}\) moles of \(O_2\)
- \(2.00 \times 10^{-2}\) moles of \(N_2O\)
Calculate the equilibrium constant, \(K\), at this temperature for the reaction:
\[ 2N_2(g) + O_2(g) \rightleftharpoons 2N_2O(g) \]
**Given:**
- \([N_2] = 2.00 \times 10^{-4} \, M\)
- \([N_2O] = 0.200 \, M\)
- \([O_2] = 0.00813 \, M\)
**Question:**
Does this represent a system at equilibrium?
[Submit Answer] [Try Another Version]
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Transcribed Image Text:**Equilibrium Calculation Exercise**
At a particular temperature, a 2.00-L flask at equilibrium contains:
- \(5.10 \times 10^{-4}\) moles of \(N_2\)
- \(2.50 \times 10^{-5}\) moles of \(O_2\)
- \(2.00 \times 10^{-2}\) moles of \(N_2O\)
Calculate the equilibrium constant, \(K\), at this temperature for the reaction:
\[ 2N_2(g) + O_2(g) \rightleftharpoons 2N_2O(g) \]
**Given:**
- \([N_2] = 2.00 \times 10^{-4} \, M\)
- \([N_2O] = 0.200 \, M\)
- \([O_2] = 0.00813 \, M\)
**Question:**
Does this represent a system at equilibrium?
[Submit Answer] [Try Another Version]
*6 item attempts remaining*
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