At a given temperature, the equilibrium constant (Kp) for the decomposition of dinitrogen tetraoxide to nitrogen dioxide is 0.154. If 0.198 atm N2O4 is sealed in a flask, what partial pressure  (in atm) of NO2 will exist at equilibrium? N2O4(g)  ⇄ 2NO2(g)

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter15: Principles Of Chemical Reactivity: Equilibria
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At a given temperature, the equilibrium constant (Kp) for the decomposition of dinitrogen tetraoxide to nitrogen dioxide is 0.154. If 0.198 atm N2O4 is sealed in a flask, what partial pressure  (in atm) of NO2 will exist at equilibrium?
N2O4(g)  ⇄ 2NO2(g)

(no scientific notation)

Expert Solution
Introduction

In equilibrium concepts, it is quite common to come across various equilibrium constants. The equilibrium constant (K) becomes quite helpful while expressing the relationship between products and reactants for a particular reaction (under equilibrium conditions). 

Given data: 

The equilibrium constant Kp is 0.154. 

Initial pressure of N2O4 is 0.198 atm. 

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