Answered: At a frequency of 2.84 GHz, and an…

At a frequency of 2.84 GHz, and an antenna diameter of 32 m, what is the angular distance between the diffraction minima around the central maximum, in arc minutes?

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Question

At a frequency of 2.84 GHz, and an antenna diameter
of 32 m, what is the angular distance between the
diffraction minima around the central maximum, in
arc minutes?

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Write down an expression for the angle of the first minimum of diffraction of light of wavelength A by a circular aperture of diameter d. Please use appropriate algebraic symbols for multiplication (* for a × b), division (/ for a/b), exponents (a^b for a³), square root (sqrt(a*b/c) for √a × b/c) etc. For Greek letters use their names e.g. "theta" (without the quotes) and for trigonometric functions use "cos", "tan", "sin", "asin" (for arc sine etc., without the quotes). Thus for Acose use A* cos theta or for A*sin‍¹ (a+b) use A*asin(a+b) etc. Please use the "Display response" button to check you entered the answer you expect. 0= Display response
Please type the answer instead of hand writting
Two narrow SIIts sepevated by 0.42 mm are IllUminated by mon0- chromattclight ot wavelength 00 407nm. Huw many brignt Vinger Can he seen on a Screen I,9cm wide Placed 18m in tron1 OF the sl1ts?