At a certain temperature, Kp = 0.23 for the reaction: N₂O4 (g) 2 NO₂ (g) At equilibrium, the pressure of N₂O4 (g) is 3.37 atm and the pressure of NO₂ (g) is 0.874 atm. The volume of the container is decreased to one-half of the original volume, and the temperature is held constant. Calculate the new equilibrium pressure of NO2 (g) In atm. Do NOT include units in your answer. If you round during your calculation, be sure to keep at least four (4) decimal places. Report your final answer to two (2) decimal places. Answer: 1.51 X

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At a certain temperature, Kp = 0.23 for the
reaction:
N₂O4 (g) 2 NO₂ (g)
At equilibrium, the pressure of N₂O4 (g) is
3.37 atm and the pressure of NO₂ (g) is
0.874 atm. The volume of the container is
decreased to one-half of the original
volume, and the temperature is held
constant. Calculate the new equilibrium
pressure of NO₂ (g) In atm.
Do NOT include units in your answer. If you
round during your calculation, be sure to
keep at least four (4) decimal places.
Report your final answer to two (2) decimal
places.
Answer:
1.51
X
The correct answer is: 1.26
Transcribed Image Text:At a certain temperature, Kp = 0.23 for the reaction: N₂O4 (g) 2 NO₂ (g) At equilibrium, the pressure of N₂O4 (g) is 3.37 atm and the pressure of NO₂ (g) is 0.874 atm. The volume of the container is decreased to one-half of the original volume, and the temperature is held constant. Calculate the new equilibrium pressure of NO₂ (g) In atm. Do NOT include units in your answer. If you round during your calculation, be sure to keep at least four (4) decimal places. Report your final answer to two (2) decimal places. Answer: 1.51 X The correct answer is: 1.26
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