At a boundary between medium 1, which has Er1=4, and medium 2, which has Er2 =3, the electric field in medium 1 is given by E1= 3 ax + 6 ay – 4 az V/m. The boundary between the media is the y=0 plane. Using electrostatic boundary conditions, find (a) E2 and the angle it makes with the y-axis, and (b) the electrostatic energy density in each region. (c) the energy inside a 1 cm3 cube in each medium. Note: Here E represents Epsilon.
At a boundary between medium 1, which has Er1=4, and medium 2, which has Er2 =3, the electric field in medium 1 is given by E1= 3 ax + 6 ay – 4 az V/m. The boundary between the media is the y=0 plane. Using electrostatic boundary conditions, find (a) E2 and the angle it makes with the y-axis, and (b) the electrostatic energy density in each region. (c) the energy inside a 1 cm3 cube in each medium. Note: Here E represents Epsilon.
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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At a boundary between medium 1, which has Er1=4, and medium 2, which has Er2 =3, the electric field in medium 1 is given by E1= 3 ax + 6 ay – 4 az V/m. The boundary between the media is the y=0 plane. Using electrostatic boundary conditions, find
(a) E2 and the angle it makes with the y-axis, and
(b) the electrostatic energy density in each region.
(c) the energy inside a 1 cm3 cube in each medium.
Note: Here E represents Epsilon.
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Step 1: Given Information
VIEWStep 2: Diagram for Boundary Condition
VIEWStep 3: Determination of Electric Field in medium 2
VIEWStep 4: Concept of angle made by electric field with boundary
VIEWStep 5: Determination of angle made by E2 with y-axis
VIEWStep 6: Determination of energy density in both medium
VIEWStep 7: Determination of energy inside a cube in medium 1
VIEWStep 8: Determination of energy inside a cube in medium 2
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