At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.08 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p*. (Round your answer up to the nearest whole number.) 150

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**Sample Size Calculation for Population Proportion**

When planning a study to estimate a population proportion with a specific level of precision, it's crucial to determine the appropriate sample size. This is calculated based on the desired confidence level and margin of error.

**Scenario:**
- **Confidence Level:** 95%
- **Margin of Error:** 0.08

The task is to determine how large a sample should be to achieve the desired level of precision without prior data available to set a planning value for \( p^* \).

Upon calculating, a sample size of 150 was entered but marked incorrect.

**Note:**
To find the correct sample size, use the formula for sample size calculation in estimating a population proportion:

\[
n = \left(\frac{Z^2 \cdot p^* \cdot (1-p^*)}{E^2}\right)
\]

Where:
- \( n \) = required sample size
- \( Z \) = Z-score (1.96 for 95% confidence)
- \( p^* \) = estimated proportion (often set to 0.5 if unknown)
- \( E \) = margin of error

Make sure to round up to the nearest whole number after calculation.
Transcribed Image Text:**Sample Size Calculation for Population Proportion** When planning a study to estimate a population proportion with a specific level of precision, it's crucial to determine the appropriate sample size. This is calculated based on the desired confidence level and margin of error. **Scenario:** - **Confidence Level:** 95% - **Margin of Error:** 0.08 The task is to determine how large a sample should be to achieve the desired level of precision without prior data available to set a planning value for \( p^* \). Upon calculating, a sample size of 150 was entered but marked incorrect. **Note:** To find the correct sample size, use the formula for sample size calculation in estimating a population proportion: \[ n = \left(\frac{Z^2 \cdot p^* \cdot (1-p^*)}{E^2}\right) \] Where: - \( n \) = required sample size - \( Z \) = Z-score (1.96 for 95% confidence) - \( p^* \) = estimated proportion (often set to 0.5 if unknown) - \( E \) = margin of error Make sure to round up to the nearest whole number after calculation.
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