At 60 °C, Kw for water is 1.0 × 10¹³. At 60 °C, a weak acid has a Ka of 1.3 x 10-4. What is the Kb for the conjugate base at this temperature?
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![### Calculating the \( K_b \) for the Conjugate Base at 60°C
At 60°C, the ion product of water (\( K_w \)) is \( 1.0 \times 10^{13} \).
Given:
- \( K_a \) for a weak acid at 60°C is \( 1.3 \times 10^{-4} \).
To find:
- The \( K_b \) for the conjugate base at this temperature.
Using the relation:
\[ K_w = K_a \times K_b \]
We can rearrange to solve for \( K_b \):
\[ K_b = \frac{K_w}{K_a} \]
So,
\[ K_b = \frac{1.0 \times 10^{13}}{1.3 \times 10^{-4}} \]
This simplifies to:
\[ K_b = \left(\frac{1.0}{1.3}\right) \times 10^{13 - (-4)} \]
\[ K_b = \left(\frac{1.0}{1.3}\right) \times 10^{17} \]
\[ K_b \approx 0.769 \times 10^{17} \]
Therefore,
\[ K_b = 7.69 \times 10^{16} \]
Next, enter the coefficient (7.69) and the exponent (16) into the corresponding input fields, then press "Enter."
#### Input Fields
- **Coefficient (green field):** 7.69
- **Exponent (yellow field):** 16
Press the "Enter" button to submit your answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F44b0d593-f487-4f0d-923f-5b6d8a9e98f3%2F8244cb45-98cc-4413-a625-30ef2370f904%2Fbq9v0tr_processed.jpeg&w=3840&q=75)
Step by step
Solved in 2 steps with 1 images
