At 500 K the reaction: PCI,(g) PCl₂(g) + Cl₂(g) has K₂ = 0.497. In an EQ mixture at 500 K, the partial pressure of PCI, is 0.860 atm and that of PCl3 is 0.350 atm. What is the partial pressure of Cl₂ in the equilibrium mixture? Solution Proceed similarly to the previous sample exercise. EQ: PCI,(g) 0.860 Kp = X = PPC13 PC12 PPC15 0.497 = (0.350)(x) (0.860) PCl3(g) + Cl₂(g) 0.350 X PC12 = 1.22 atm
At 500 K the reaction: PCI,(g) PCl₂(g) + Cl₂(g) has K₂ = 0.497. In an EQ mixture at 500 K, the partial pressure of PCI, is 0.860 atm and that of PCl3 is 0.350 atm. What is the partial pressure of Cl₂ in the equilibrium mixture? Solution Proceed similarly to the previous sample exercise. EQ: PCI,(g) 0.860 Kp = X = PPC13 PC12 PPC15 0.497 = (0.350)(x) (0.860) PCl3(g) + Cl₂(g) 0.350 X PC12 = 1.22 atm
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Can you redo that calculation and explain the concept?
![At 500 K the reaction: PCI,(g)
PCl₂(g) + Cl₂(g) has K₂ = 0.497.
In an EQ mixture at 500 K, the partial pressure of PCI, is 0.860 atm and that of
PCl3 is 0.350 atm. What is the partial pressure of Cl₂ in the equilibrium mixture?
Solution
Proceed similarly to the previous sample exercise.
EQ:
PCI,(g)
0.860
Kp
=
X =
PPC13 PC12
PPC15
0.497 = (0.350)(x)
(0.860)
PCl3(g) + Cl₂(g)
0.350
X
PC12
=
1.22 atm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F637a8243-98d2-45ca-8dd1-4e9d7d0f97ca%2Fe6a3c6bc-c732-4b22-b81d-cb0d21c0211c%2Fnoi7p8b.jpeg&w=3840&q=75)
Transcribed Image Text:At 500 K the reaction: PCI,(g)
PCl₂(g) + Cl₂(g) has K₂ = 0.497.
In an EQ mixture at 500 K, the partial pressure of PCI, is 0.860 atm and that of
PCl3 is 0.350 atm. What is the partial pressure of Cl₂ in the equilibrium mixture?
Solution
Proceed similarly to the previous sample exercise.
EQ:
PCI,(g)
0.860
Kp
=
X =
PPC13 PC12
PPC15
0.497 = (0.350)(x)
(0.860)
PCl3(g) + Cl₂(g)
0.350
X
PC12
=
1.22 atm
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