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At 4:00pm, a thermometer reading of 28 deg C is taken outside where the ambient temperature is –11 deg C. At 4:05 pm, the thermometer reads 8 deg above zero. After a while, the thermometer is returned to the room maintained at 28 deg C. At 4:12pm, the thermometer reads 15 deg C. When was the thermometer returned to the room?

At 4:00pm, a thermometer reading of 28 deg C is taken outside where the ambient temperature is –11 deg C. At 4:05 pm, the thermometer reads 8 deg above zero. After a while, the thermometer is returned to the room maintained at 28 deg C. At 4:12pm, the thermometer reads 15 deg C. When was the thermometer returned to the room?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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NEWTON’S LAW OF COOLING, JOINT PROPORTIONS

A topic from Differential Calculus

 

Newton's law of cooling formula

u=Ce-kt+T

 

Joint proportions formula

x/(N-x)=CeNkt 

 

Choose if the problem state Newton's law of cooling or Joint Proportions. Thankyou!

 

 

 

 

At 4:00pm, a thermometer reading of 28 deg C is taken outside where the ambient temperature is -11 deg C. At 4:05 pm, the thermometer reads 8 deg above zero. After a while, the thermometer is returned to the room maintained at 28 deg C. At 4:12pm, the thermometer reads 15 deg C. When was the thermometer returned to the room?
Transcribed Image Text:At 4:00pm, a thermometer reading of 28 deg C is taken outside where the ambient temperature is -11 deg C. At 4:05 pm, the thermometer reads 8 deg above zero. After a while, the thermometer is returned to the room maintained at 28 deg C. At 4:12pm, the thermometer reads 15 deg C. When was the thermometer returned to the room?
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