At 25 °C, what is the hydroxide ion concentration, [OH¯], in an aqueous solution with a hydrogen ion concentration of H+]-2.9 х 10-9 M? [OH"] = M

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### Determining Hydroxide Ion Concentration

**Question:**
At 25 °C, what is the hydroxide ion concentration, \([OH^-]\), in an aqueous solution with a hydrogen ion concentration of \([H^+]=2.9 \times 10^{-9}\) M?

**Solution:**
To find the hydroxide ion concentration, \([OH^-]\), we can use the relationship between the concentrations of hydrogen ions (\([H^+]\)) and hydroxide ions (\([OH^-]\)) for water at 25 °C. The product of these concentrations is the ion-product constant for water (\(K_w\)):

\[ K_w = [H^+][OH^-] = 1.0 \times 10^{-14} \]

Given:
\[ [H^+] = 2.9 \times 10^{-9} \, \text{M} \]

We can rearrange the equation to solve for \([OH^-]\):

\[ [OH^-] = \frac{K_w}{[H^+]} \]

Substitute the given values:

\[ [OH^-] = \frac{1.0 \times 10^{-14}}{2.9 \times 10^{-9}} \]

Perform the calculation:

\[ [OH^-] = \frac{1.0 \times 10^{-14}}{2.9 \times 10^{-9}} = 3.45 \times 10^{-6} \, \text{M} \]

**Answer:**
\[ \mathbf{[OH^-] = 3.45 \times 10^{-6} \, M} \]

In the blank provided, you would enter the hydroxide ion concentration value calculated above.
Transcribed Image Text:### Determining Hydroxide Ion Concentration **Question:** At 25 °C, what is the hydroxide ion concentration, \([OH^-]\), in an aqueous solution with a hydrogen ion concentration of \([H^+]=2.9 \times 10^{-9}\) M? **Solution:** To find the hydroxide ion concentration, \([OH^-]\), we can use the relationship between the concentrations of hydrogen ions (\([H^+]\)) and hydroxide ions (\([OH^-]\)) for water at 25 °C. The product of these concentrations is the ion-product constant for water (\(K_w\)): \[ K_w = [H^+][OH^-] = 1.0 \times 10^{-14} \] Given: \[ [H^+] = 2.9 \times 10^{-9} \, \text{M} \] We can rearrange the equation to solve for \([OH^-]\): \[ [OH^-] = \frac{K_w}{[H^+]} \] Substitute the given values: \[ [OH^-] = \frac{1.0 \times 10^{-14}}{2.9 \times 10^{-9}} \] Perform the calculation: \[ [OH^-] = \frac{1.0 \times 10^{-14}}{2.9 \times 10^{-9}} = 3.45 \times 10^{-6} \, \text{M} \] **Answer:** \[ \mathbf{[OH^-] = 3.45 \times 10^{-6} \, M} \] In the blank provided, you would enter the hydroxide ion concentration value calculated above.
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