At 1 atm, how much energy is required to heat 49.0 g H,O(s) at –10.0 °C to H,O(g) at 149.0 °C?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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At 1 atm, how much energy is required to heat 49.0 g H, O(s) at –10.0 °C to H, O(g) at 149.0 °C?
Transcribed Image Text:At 1 atm, how much energy is required to heat 49.0 g H, O(s) at –10.0 °C to H, O(g) at 149.0 °C?
per mole
6010. J/mol
Quantity
Enthalpy of fusion at 0°C
Enthalpy of vaporization at 100°C
Specific heat of solid H2O (ice)
per gram
333.6 J/g
2257 J/g
40660 J/mol
2.087 J/(g-°C) * 37.60 J/(mol-°C) *
| 4.184 J/(g.°C) * 75.37 J/(mol-°C) *
Specific heat of gaseous H2O (steam) 2.000 J/(g-°C) * 36.03 J/(mol-°C) *
Specific heat of liquid H2O (water)
Transcribed Image Text:per mole 6010. J/mol Quantity Enthalpy of fusion at 0°C Enthalpy of vaporization at 100°C Specific heat of solid H2O (ice) per gram 333.6 J/g 2257 J/g 40660 J/mol 2.087 J/(g-°C) * 37.60 J/(mol-°C) * | 4.184 J/(g.°C) * 75.37 J/(mol-°C) * Specific heat of gaseous H2O (steam) 2.000 J/(g-°C) * 36.03 J/(mol-°C) * Specific heat of liquid H2O (water)
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