*Assuming vin(t)=2sin(1000ft) volts and using simplified (2nd) diode approximation, the waveforms ofVin(t) and the load voltage VRL(t) are shown asVin(t)2V-2V+VRL(t)1.5V-OV 1W1t21314 t, ms4t, msNOTES:The diode only conducts from t1 to t2 for every input cycle when vin(t)2vf. When the diode isconducting, VRL(t)=vin(t)-vf=2sin(1000nt)-0.5 volts, When the diode is not conducting, VRL(t)=0V.DETERMINE AVERAGE VALUE AND RMS OF VRL(t): SHOW COMPLETE SOLUTION (SUGGESTED ANSWERS 0.4066 AND 0.6941)(c) The average value and RMS value of VRL(t). Hint: The formulas for half-wave rectified sine cannot be used. Solve by evaluating the general solutions that involve integration.

Answered: Image /qna-images/answer/8e6fa293-7e73-48b0-89b4-9d54304d683d.jpg

* Assuming vin(t)=2sin(1000ft) volts and using simplified (2nd) diode approximation, the waveforms of Vin(t) and the load voltage VRL(t) are shown as Vin(t) 2V W m VRL(t) 1 t2 -2V+ 1.5V- OV 1 13 14 t, ms 4t, ms NOTES: The diode only conducts from t1 to t2 for every input cycle when vin(t)2vf. When the diode is conducting, VRL(t)=vin(t)-vf=2sin(1000xt)-0.5 volts, When the diode is not conducting, VRL(t)=0V. DETERMINE AVERAGE VALUE AND RMS OF VRL(t): SHOW COMPLETE SOLUTION (SUGGESTED ANSWERS 0.4066 AND 0.6941) (c) The average value and RMS value of VRL(t). Hint: The formulas for half-wave rectified sine can not be used. Solve by evaluating the general solutions that involve integration.

* Assuming vin(t)=2sin(1000ft) volts and using simplified (2nd) diode approximation, the waveforms of Vin(t) and the load voltage VRL(t) are shown as Vin(t) 2V W m VRL(t) 1 t2 -2V+ 1.5V- OV 1 13 14 t, ms 4t, ms NOTES: The diode only conducts from t1 to t2 for every input cycle when vin(t)2vf. When the diode is conducting, VRL(t)=vin(t)-vf=2sin(1000xt)-0.5 volts, When the diode is not conducting, VRL(t)=0V. DETERMINE AVERAGE VALUE AND RMS OF VRL(t): SHOW COMPLETE SOLUTION (SUGGESTED ANSWERS 0.4066 AND 0.6941) (c) The average value and RMS value of VRL(t). Hint: The formulas for half-wave rectified sine can not be used. Solve by evaluating the general solutions that involve integration.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

R VD 3cos(1000nt) VOUT 0.7 V What are the minimum and maximum values of Vout assuming the offset model for a diode with Von = 0,7 V for the input signal shown below? Chọn một: O a. Minimum -3 V, maximum 1.4 V O b. Minimum 1.4 V, maximum 3 V O c. Minimum 0.7 V, maximum 3 V O d. Minimum -3 V maximum 0.7 V O e. Minimum -3 V, maximum 3 V
Please show me how to solve the following practice problems in step by step solution Than you so much!
double clipper circuit Zener diodes 1N4733A has a voltage of 5.1 V and 1N4735A has a voltage of 6.2 V with a resistor R=300ohms has been used. you may like to increase the input to a 12 VRMS AC source in order to see the clipping at 7volt. Please, Do the theoretical calculations and plot the expected waveforms by hand. ( I have its multisim design and only needs theoretical calculation and hand drawn graph of it to compare to its data that I have collected from multism.) Thanks
image 93
Quèstion 15 Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to IL-DE 205A iL-DC 220V ams 5OH23 VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the above SHOT ON RED MAGIC 5S POWERED BY NUBIA
In the given circuit, D1 is Silicon diode and D2 is a zener diode with breakdown voltage of 6.8V. Assuming RC time constant of circuit >> T. Find the Maximum and Minimum value of the output waveform.
1.Find condition to know Diode on or off, Von = 0.7V. 2 Find relative equation between Vo and Vin
After solving a circuit with ideal diodes (Vf=0), what check is necessary for diodes initially assumed to be on? Off? We must check to see that reverse voltage appears across all diodes assumed to be on, and we must check to see that forward current flows in diodes assumed to be off We must check to see that forward current flows in diodes assumed to be on, and we must check to see that reverse voltage appears across all diodes assumed to be off
For a certain 12 V zener diode, a 10 mA change in zener current produces a 0.05 V change in zener voltage. The zener impedance for this current range is O a. 50 Ob. 10 - c.0.1 Ω Od. 10 Q
For a certain 12 V zener diode, a 10 mA change in zener current produces a 0.05 V change in zener voltage. The zener impedance for this current range is O a. 50 Ob. 10 - c.0.1 Ω Od. 10 Q
1. For each of these circuits, find an expression for Vout as a function of Vin and the components given. Use the exponential model for your diode (ID = IseVD/VT). Then, if we set Is = 10-¹4A, 1V, find the minimum positive power supply needed for the expression to R = 10k and Vin = hold true. a. Vin o b. Vin o + R M -1₁ Vout Vout R
Find Idc, Vdc and the capacitance that will force the Vr(pp) to 3mV. Draw the output waveform across the capacitor. Fin=60Hz.