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Assuming the only heat generated is via
fission itself, and that 207.1 MeV of
energy is recoverable per fission reaction
in 239Pu, deduce the total rate of
consumption of 239Pu fuel in g/day for a
reactor that operates at 1 MWth-
[Data: sigma_a = 1018.9 b, sigma_f =
747.4 b]
%3D
1.631 x 105 g
8.776 x 10-6 g
3.187 x 106 g
1.196 x 10-5 g

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