The following statement always evaluates to 1 (True or False): x > 0 || -x >= 0 True False
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- Assuming the following code: int x = myfunction1(); /* arbitrary value */ int y = myfunction2(); /* arbitrary value */ int z = myfunction3(); /* arbitrary value */ //convert to double double dx = (double) x; double dy = (double) y; double dz = (double) z; unsigned ux = x; unsigned uy = y; The following statement always evaluates to 1 (True or False): (dx + dy) + dz == dx + (dy + dz) True FalseAssuming the following code: int x = myfunction1(); /* arbitrary value */ int y = myfunction2(); /* arbitrary value */ int z = myfunction3(); /* arbitrary value */ //convert to double double dx = (double) x; double dy = (double) y; double dz = (double) z; unsigned ux = x; unsigned uy = y; The following statement always evaluates to 1 (True or False): dx - dy == (double) (x-y) Question 3 options: True False// declare and assign an int a value of 10 // declare and assign a double a value of 5.6 // declare and assign a boolean a value of true 3 4 5n 6. 7 } C
- #include <stdio.h>#include <stdlib.h> //declaring variables globally to calculate coinsint cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //calculate change//pass change variable by addressvoid calculateChange(int* change) {//calculate change only if change is positiveif(*change > 0) {if(*change >= 50) {*change -= 50;cent50++;}else if(*change >= 20) {*change -= 20;cent20++;}else if(*change >= 10) {*change -= 10;cent10++;}else if(*change >= 05) {*change -= 05;cent05++;}//call calculateChange recursively calculateChange(change);}} // function to display the cents valuesvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50);if(cent20)printf("\n20 Cents : %d coins", cent20);if(cent10)printf("\n10 Cents : %d coins", cent10);if(cent05)printf("\n05 Cents : %d coins", cent05);//reset all cent variables with 0cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //take change input from user//change variable passed addressvoid TakeChange(int*…int x1 = 66; int y1 = 39; int d; _asm { } mov EAX, X1; mov EBX, y1; push EAX; push EBX; pop ECX mov d, ECX; What is d in decimal format?When you perform arithmetic operations with operands of different types, such as adding an int and a float, ____________. C# chooses a unifying type for the result you must choose a unifying type for the result you must provide a cast you receive an error message
- Given the following declaration: int x; int* p; Which of the following expressions is allowed? Select one: a. p = x; b. p = &x; %3D C. p = *x; d. x = p;#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…
- #include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…Evaluate the following expressions, assume the following declarations: int x = 4 /3 * 2; int y = 9/ 2; int num = 6; num *= x + y; What is the value of the num after expression is evaluated?