Assuming the equilibrium constants for the following two chemical reactions are 10.0 (K1) and 1.50x10-8 (K2), respectively: 2C(s) + O2(aq) <=> 2CO(aq) K1 2CO2(aq) <=> 2CO(aq) + O2(aq) K2 What is the equilibrium constant for the chemical reaction shown below? C(s) +02(aq) <=> CO2(aq) O 2.48 x 104 2.58 x 104 6.67 x 108 9.60 1.61 x 102

Chemistry
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**Understanding Equilibrium Constants**

In this section, we are considering the equilibrium constants for two chemical reactions. The equilibrium constants are given as follows:

- \( K_1 = 10.0 \)
- \( K_2 = 1.50 \times 10^{-8} \)

### Reactions

1. **Reaction 1:** 
   \[ 2C(s) + O_2(aq) \leftrightarrow 2CO(aq) \]
   - Equilibrium constant: \( K_1 \)

2. **Reaction 2:**
   \[ 2CO_2(aq) \leftrightarrow 2CO(aq) + O_2(aq) \]
   - Equilibrium constant: \( K_2 \)

**Question:**

What is the equilibrium constant for the following chemical reaction?

\[ \frac{1}{2} C(s) + \frac{1}{2} O_2(aq) \leftrightarrow \frac{1}{2} CO_2(aq) \]

**Answer Choices:**

- \( 2.48 \times 10^4 \)
- \( 2.58 \times 10^4 \)
- \( 6.67 \times 10^8 \)
- \( 9.60 \)
- **Selected Answer:** \( 1.61 \times 10^2 \)

By analyzing the given data and understanding the transformations between the given reactions, the equilibrium constant for the provided reaction can be determined using the relationship between the original constants \( K_1 \) and \( K_2 \). The correct answer, as highlighted, is \( 1.61 \times 10^2 \).
Transcribed Image Text:**Understanding Equilibrium Constants** In this section, we are considering the equilibrium constants for two chemical reactions. The equilibrium constants are given as follows: - \( K_1 = 10.0 \) - \( K_2 = 1.50 \times 10^{-8} \) ### Reactions 1. **Reaction 1:** \[ 2C(s) + O_2(aq) \leftrightarrow 2CO(aq) \] - Equilibrium constant: \( K_1 \) 2. **Reaction 2:** \[ 2CO_2(aq) \leftrightarrow 2CO(aq) + O_2(aq) \] - Equilibrium constant: \( K_2 \) **Question:** What is the equilibrium constant for the following chemical reaction? \[ \frac{1}{2} C(s) + \frac{1}{2} O_2(aq) \leftrightarrow \frac{1}{2} CO_2(aq) \] **Answer Choices:** - \( 2.48 \times 10^4 \) - \( 2.58 \times 10^4 \) - \( 6.67 \times 10^8 \) - \( 9.60 \) - **Selected Answer:** \( 1.61 \times 10^2 \) By analyzing the given data and understanding the transformations between the given reactions, the equilibrium constant for the provided reaction can be determined using the relationship between the original constants \( K_1 \) and \( K_2 \). The correct answer, as highlighted, is \( 1.61 \times 10^2 \).
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