Assuming the equilibrium constants for the following two chemical reactions are 10.0 (K1) and 1.50x10-8 (K2), respectively: 2C(s) + O2(aq) <=> 2CO(aq) K1 2CO2(aq) <=> 2CO(aq) + O2(aq) K2 What is the equilibrium constant for the chemical reaction shown below? C(s) +02(aq) <=> CO2(aq) O 2.48 x 104 2.58 x 104 6.67 x 108 9.60 1.61 x 102
Assuming the equilibrium constants for the following two chemical reactions are 10.0 (K1) and 1.50x10-8 (K2), respectively: 2C(s) + O2(aq) <=> 2CO(aq) K1 2CO2(aq) <=> 2CO(aq) + O2(aq) K2 What is the equilibrium constant for the chemical reaction shown below? C(s) +02(aq) <=> CO2(aq) O 2.48 x 104 2.58 x 104 6.67 x 108 9.60 1.61 x 102
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Understanding Equilibrium Constants**
In this section, we are considering the equilibrium constants for two chemical reactions. The equilibrium constants are given as follows:
- \( K_1 = 10.0 \)
- \( K_2 = 1.50 \times 10^{-8} \)
### Reactions
1. **Reaction 1:**
\[ 2C(s) + O_2(aq) \leftrightarrow 2CO(aq) \]
- Equilibrium constant: \( K_1 \)
2. **Reaction 2:**
\[ 2CO_2(aq) \leftrightarrow 2CO(aq) + O_2(aq) \]
- Equilibrium constant: \( K_2 \)
**Question:**
What is the equilibrium constant for the following chemical reaction?
\[ \frac{1}{2} C(s) + \frac{1}{2} O_2(aq) \leftrightarrow \frac{1}{2} CO_2(aq) \]
**Answer Choices:**
- \( 2.48 \times 10^4 \)
- \( 2.58 \times 10^4 \)
- \( 6.67 \times 10^8 \)
- \( 9.60 \)
- **Selected Answer:** \( 1.61 \times 10^2 \)
By analyzing the given data and understanding the transformations between the given reactions, the equilibrium constant for the provided reaction can be determined using the relationship between the original constants \( K_1 \) and \( K_2 \). The correct answer, as highlighted, is \( 1.61 \times 10^2 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7dc34f44-c0da-4881-92cf-f3f7cc0de69f%2F23476f3b-0694-402d-af08-f76f277b69ea%2Fjzzn9tf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Understanding Equilibrium Constants**
In this section, we are considering the equilibrium constants for two chemical reactions. The equilibrium constants are given as follows:
- \( K_1 = 10.0 \)
- \( K_2 = 1.50 \times 10^{-8} \)
### Reactions
1. **Reaction 1:**
\[ 2C(s) + O_2(aq) \leftrightarrow 2CO(aq) \]
- Equilibrium constant: \( K_1 \)
2. **Reaction 2:**
\[ 2CO_2(aq) \leftrightarrow 2CO(aq) + O_2(aq) \]
- Equilibrium constant: \( K_2 \)
**Question:**
What is the equilibrium constant for the following chemical reaction?
\[ \frac{1}{2} C(s) + \frac{1}{2} O_2(aq) \leftrightarrow \frac{1}{2} CO_2(aq) \]
**Answer Choices:**
- \( 2.48 \times 10^4 \)
- \( 2.58 \times 10^4 \)
- \( 6.67 \times 10^8 \)
- \( 9.60 \)
- **Selected Answer:** \( 1.61 \times 10^2 \)
By analyzing the given data and understanding the transformations between the given reactions, the equilibrium constant for the provided reaction can be determined using the relationship between the original constants \( K_1 \) and \( K_2 \). The correct answer, as highlighted, is \( 1.61 \times 10^2 \).
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