Assuming that your mom is pregnant and due in 100 days. Consider a mean of 100 days and standard deviation of 8 days for having a child. You will be sent to Taiwan as an exchange student and will return in 85 days and have to go on another visit in 107th day. What is the probability that the birth will occur before your second trip? Just provide the z value

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A: According to the given information, we have Mean = 5 minutes Standard deviation = 1 minutes

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A:

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A:

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A: GivenMean(μ)=15standard deviation(σ)=4

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A: The mean is 73 and the standard deviation is 15.9.

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A: a) It is given that the mean is 266 and standard deviation is 15.

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A: Given: Meanμ=747Standard Deviationσ=21 The probability that it will weigh between 691 and 804 grams…

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A:

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A: Given mean(μ)=265standard deviation(σ)=15

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A: given data,normal distribution μ=5σ=3probability that person will wait more than 9 minutes =?

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Q: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 5…

A: Here, mean is 5 and standard deviation is 3. We will use z-standard normal distribution.

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A: Answer: From the given data, Mean (μ) = 510 Standard deviation (σ) = 33 X~ Normal distribution (μ,σ)

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Q: Edit question fast please. The lengths of Atlantic Croaker Fish are normally distributed with mean…

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Q: A particular fruit's weights are normally distributed, with a mean of 656 grams and a standard…

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A:

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: We have  to find required probability and correct graph....