Assuming no sequencing errors, two DNA sequences TGAC and CATGA can beassembled into the original sequence in two different ways: TGACATGA andCATGAC. What is the probability of the original sequence being CATGAC byrandom chance? (Assume that each of the four nucleotides occurs with the samefrequency.)O (1/4)4O (1/4)2O 1/4O (1/4)3

Given Assuming no sequencing errors, two DNA sequences TGAC and CATGA can be assembled into the…

Answered: Assuming no sequencing errors, two DNA…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Urn A has 3 white and 9 red balls. Urn B has 15 white and 13 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a white ball is selected. What is the probability that the coin landed heads? 0.30
Ab 45 Economics Assume that 5% of the students in 200-level econ courses choose not to ever come to classes. For a 200-level econ course with 60 students in the class,what is the probability that less than 20 students will come?
can you answer question 3 subsection A-B?
5c The genotype of an organism can be either normal (wild type, W) or mutant (M). Each generation, a wild type individual has probability 0.03 of having a mutant offspring, and a mutant has probability 0.005 of having a wild type offspring. Calculate the probability of a string of the following genotypes in successive generations: WWW.
Example 2.3.28 A lot contains 20 articles. The probability that the lot contains exactly 2 defective articles is 0.4, and the probability that it contains 3 defective articles is 0.6. The articles are drawn one-by-one at random, and without replacement and they are tested till all defectives are found. What is the probability that the testing procedure ends at the twelfth testing?
4-4: Urn 1 contains 5 red balls and 3 black balls. Urn 2 contains 3 red balls and 1 black ball. Urn 3 contains 4 red balls and 2 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red.
3 of 30 (1 complete) The access code for a safe consists of three digits. Each digit can be any number from 0 through 9, and each digit can be repeated. Complete parts (a) through (c). (a) Find the number of possible access codes. (b) What is the probability of randomly selecting the correctaccess code ori the first try? (c) What is the probability of not selecting the correct access code on the first try? (a) Find the number of possible access codes. The number of different codes available is (b) What is the probability of randomly selecting the correct access code on the first try? The probability of randomly selecting the correct access code is (Round to three decimal places as needed.) (c) What is the probability of not selecting the correct access code on the first try? The probability of not selecting the correct access code is (Round to three decimal places as needed.)
Binary digits, that is 0 and 1 are sent down a noisy communications channel. They are received as sent with probability 0.9 but errors occur with probability 0.1. To improve the reliability of the channel we repeat each digit in the message three times. (a) Let A=”101 was received” and B=”111 was sent”. What is the probability that 111 was sent given that we received 101?, i.e., What is P(B|A)? (b) Let A=”000 was received” and B=”111 was sent”. What is the probability that 111 was sent given that we received 000?i.e., What is P(B|A)?

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