Assuming air resistance with drag ratio-velocity for an object, initially suspended at the heightYo = 500 m above the Earth and dropped with v(0) = 0 m/s. Usegravitational accelerationg = 9. 8 m/s² . Round your answer to 2decimal places.=0.35 find the terminalт

Assuming air resistance with drag ratio =0.35 find the terminal velocity for an object, initially suspended at the height Yo = 500 m above the Earth and dropped with v(0) = 0 m/s. gravitational accelerationg = 9. 8 m/s² . Round your answer to 2 decimal places. m Use

Assuming air resistance with drag ratio =0.35 find the terminal velocity for an object, initially suspended at the height Yo = 500 m above the Earth and dropped with v(0) = 0 m/s. gravitational accelerationg = 9. 8 m/s² . Round your answer to 2 decimal places. m Use

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Question

Assuming air resistance with drag ratio-
velocity for an object, initially suspended at the height
Yo = 500 m above the Earth and dropped with v(0) = 0 m/s. Use
gravitational accelerationg = 9. 8 m/s² . Round your answer to 2
decimal places.
=0.35 find the terminal
т

Expert Solution

Step 1

Newton's Second Law of Motion

According to Newton's Second Law of motion, the rate of change of momentum of an object is directly proportional to the net external force acting on the object. Mathematically it is given as

$\sum_{i = 1}^{n} F_{i} = m a$

The LHS is the net external force acting on an object of mass m causing an acceleration a.