Assume Z has a standard normal distribution. Use Appendix Table III to determine the value for z that solves each of the following: (a) P(-z < Z < z) = 0.95. Z = (Round the answer to 2 decimal places.) (b) P(-z < Z < z) = 0.99.

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Assume Z has a standard normal
distribution. Use Appendix Table III to
determine the value for z that solves each
of the following:
(a) P(-z < Z < z) = 0.95.
Z =
(Round the answer to 2 decimal places.)
(b) P(− z < Z < z) = 0.99.
Transcribed Image Text:Assume Z has a standard normal distribution. Use Appendix Table III to determine the value for z that solves each of the following: (a) P(-z < Z < z) = 0.95. Z = (Round the answer to 2 decimal places.) (b) P(− z < Z < z) = 0.99.
(c) P(− z < Z < z) = 0.64.
Z =
(Round the answer to 2 decimal places.)
(d) P(− z < Z < z) = 0.9973.
Z =
i
(Round the answer to 1 decimal place.)
Transcribed Image Text:(c) P(− z < Z < z) = 0.64. Z = (Round the answer to 2 decimal places.) (d) P(− z < Z < z) = 0.9973. Z = i (Round the answer to 1 decimal place.)
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