Assume you dissolve 6.73 g NA2CO3 in enough water to make 250. mL of solution. (Molar mass of Na2CO3 = 106 g/mol.) What is the molarity of the sodium carbonate? Report your answer with three significant figures. %3D

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Chapter1: Chemical Foundations
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**Text for Educational Website:**

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**Problem Statement:**

Assume you dissolve 6.73 g of Na₂CO₃ in enough water to make 250. mL of solution. (Molar mass of Na₂CO₃ = 106 g/mol.) What is the molarity of the sodium carbonate? Report your answer with three significant figures.

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**Explanation:**

This problem involves calculating the molarity of a sodium carbonate solution. Molarity (M) is defined as the number of moles of solute (in this case, Na₂CO₃) per liter of solution.

**Steps to Solve:**

1. **Calculate the number of moles of Na₂CO₃:**

   \[
   \text{Moles of Na₂CO₃} = \frac{\text{Mass of Na₂CO₃}}{\text{Molar Mass of Na₂CO₃}} = \frac{6.73 \, \text{g}}{106 \, \text{g/mol}}
   \]

2. **Convert the volume from milliliters to liters:**

   \[
   250. \, \text{mL} = 0.250 \, \text{L}
   \]

3. **Calculate the molarity:**

   \[
   M = \frac{\text{Moles of Na₂CO₃}}{\text{Volume in Liters}}
   \]

After completing these calculations, ensure the answer is reported with three significant figures, as specified.
Transcribed Image Text:**Text for Educational Website:** --- **Problem Statement:** Assume you dissolve 6.73 g of Na₂CO₃ in enough water to make 250. mL of solution. (Molar mass of Na₂CO₃ = 106 g/mol.) What is the molarity of the sodium carbonate? Report your answer with three significant figures. --- **Explanation:** This problem involves calculating the molarity of a sodium carbonate solution. Molarity (M) is defined as the number of moles of solute (in this case, Na₂CO₃) per liter of solution. **Steps to Solve:** 1. **Calculate the number of moles of Na₂CO₃:** \[ \text{Moles of Na₂CO₃} = \frac{\text{Mass of Na₂CO₃}}{\text{Molar Mass of Na₂CO₃}} = \frac{6.73 \, \text{g}}{106 \, \text{g/mol}} \] 2. **Convert the volume from milliliters to liters:** \[ 250. \, \text{mL} = 0.250 \, \text{L} \] 3. **Calculate the molarity:** \[ M = \frac{\text{Moles of Na₂CO₃}}{\text{Volume in Liters}} \] After completing these calculations, ensure the answer is reported with three significant figures, as specified.
What is the molarity of a solution that is made by dissolving 98.2 g of NaCl in 392 mL of water? The molar mass of NaCl is 58.44 g/mol. Express your answer with three significant digits.
Transcribed Image Text:What is the molarity of a solution that is made by dissolving 98.2 g of NaCl in 392 mL of water? The molar mass of NaCl is 58.44 g/mol. Express your answer with three significant digits.
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