Assume you dissolve 6.73 g NA2CO3 in enough water to make 250. mL of solution. (Molar mass of Na2CO3 = 106 g/mol.) What is the molarity of the sodium carbonate? Report your answer with three significant figures. %3D
Assume you dissolve 6.73 g NA2CO3 in enough water to make 250. mL of solution. (Molar mass of Na2CO3 = 106 g/mol.) What is the molarity of the sodium carbonate? Report your answer with three significant figures. %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Text for Educational Website:**
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**Problem Statement:**
Assume you dissolve 6.73 g of Na₂CO₃ in enough water to make 250. mL of solution. (Molar mass of Na₂CO₃ = 106 g/mol.) What is the molarity of the sodium carbonate? Report your answer with three significant figures.
---
**Explanation:**
This problem involves calculating the molarity of a sodium carbonate solution. Molarity (M) is defined as the number of moles of solute (in this case, Na₂CO₃) per liter of solution.
**Steps to Solve:**
1. **Calculate the number of moles of Na₂CO₃:**
\[
\text{Moles of Na₂CO₃} = \frac{\text{Mass of Na₂CO₃}}{\text{Molar Mass of Na₂CO₃}} = \frac{6.73 \, \text{g}}{106 \, \text{g/mol}}
\]
2. **Convert the volume from milliliters to liters:**
\[
250. \, \text{mL} = 0.250 \, \text{L}
\]
3. **Calculate the molarity:**
\[
M = \frac{\text{Moles of Na₂CO₃}}{\text{Volume in Liters}}
\]
After completing these calculations, ensure the answer is reported with three significant figures, as specified.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3cee4417-a7cf-430c-b77c-2ef456656a7a%2Fadd4ff3a-1ade-404f-943d-be8901950db2%2Fk8srp5p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Text for Educational Website:**
---
**Problem Statement:**
Assume you dissolve 6.73 g of Na₂CO₃ in enough water to make 250. mL of solution. (Molar mass of Na₂CO₃ = 106 g/mol.) What is the molarity of the sodium carbonate? Report your answer with three significant figures.
---
**Explanation:**
This problem involves calculating the molarity of a sodium carbonate solution. Molarity (M) is defined as the number of moles of solute (in this case, Na₂CO₃) per liter of solution.
**Steps to Solve:**
1. **Calculate the number of moles of Na₂CO₃:**
\[
\text{Moles of Na₂CO₃} = \frac{\text{Mass of Na₂CO₃}}{\text{Molar Mass of Na₂CO₃}} = \frac{6.73 \, \text{g}}{106 \, \text{g/mol}}
\]
2. **Convert the volume from milliliters to liters:**
\[
250. \, \text{mL} = 0.250 \, \text{L}
\]
3. **Calculate the molarity:**
\[
M = \frac{\text{Moles of Na₂CO₃}}{\text{Volume in Liters}}
\]
After completing these calculations, ensure the answer is reported with three significant figures, as specified.

Transcribed Image Text:What is the molarity of a solution that is made by dissolving 98.2 g of NaCl in 392 mL of water? The molar mass of NaCl is 58.44 g/mol. Express your answer with three significant digits.
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