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Assume x and y are functions of t. Evaluate dt y³ = 2x² +6: dx dt -=4, x= 1, y = 2 for the following. (Round to two decimal places as needed.)

Assume x and y are functions of t. Evaluate dt y³ = 2x² +6: dx dt -=4, x= 1, y = 2 for the following. (Round to two decimal places as needed.)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement: Calculus Derivative Evaluation** Assume \(x\) and \(y\) are functions of \(t\). Evaluate \(\frac{dy}{dt}\) for the following conditions: \[y^3 = 2x^2 + 6;\] \[\frac{dx}{dt} = 4, \; x = 1, \; y = 2\] \[ \frac{dy}{dt} = \; \_\_\_\_ \; (Round to two decimal places as needed.)\]
Transcribed Image Text:**Problem Statement: Calculus Derivative Evaluation** Assume \(x\) and \(y\) are functions of \(t\). Evaluate \(\frac{dy}{dt}\) for the following conditions: \[y^3 = 2x^2 + 6;\] \[\frac{dx}{dt} = 4, \; x = 1, \; y = 2\] \[ \frac{dy}{dt} = \; \_\_\_\_ \; (Round to two decimal places as needed.)\]
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