**Stack Operations and Value Determination**Assume we have the following stack operations, where the numeric values are pushed onto the stack and popped off into variable (or register) `r1`:```push(42)push(15)r1 = pop()push(9)push(20)r1 = pop()r1 = pop()r1 = pop()push(15)```**Question:**What is the value of `r1` after the operations complete?**Options:**- A. 9- B. 15- C. 20- D. 42**Explanation:**1. **push(42)**: The stack is now [42].2. **push(15)**: The stack becomes [42, 15].3. **r1 = pop()**: Pop the top value (15), so `r1 = 15`. The stack is now [42].4. **push(9)**: The stack updates to [42, 9].5. **push(20)**: The stack updates to [42, 9, 20].6. **r1 = pop()**: Pop the top value (20), so `r1 = 20`. The stack is now [42, 9].7. **r1 = pop()**: Pop the top value (9), so `r1 = 9`. The stack is now [42].8. **r1 = pop()**: Pop the top value (42), so `r1 = 42`. The stack is now empty [].9. **push(15)**: The stack updates to [15].After all operations, the final value of `r1` is 42.**Correct Answer: D. 42**

Stack is linear data structure. Stack works in LIFO order that means element which is inserted first…

Assume we have the following stack operations, where the numeric values are pushed onto the stack and popped off into variable (or register) r1: push (42) push (15) r1 = pop() push (9) push (20) r1 = pop() r1= pop() r1 = pop() push (15) What is the value of r1 after the operations complete? O A. 9 OB. 15 OC. 20 O D. 42

Assume we have the following stack operations, where the numeric values are pushed onto the stack and popped off into variable (or register) r1: push (42) push (15) r1 = pop() push (9) push (20) r1 = pop() r1= pop() r1 = pop() push (15) What is the value of r1 after the operations complete? O A. 9 OB. 15 OC. 20 O D. 42

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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