Assume we have available a fair die with outcomes, 1, 2, 3, 4, 5, and 6 and with probability mass function p(1) = P(2) = p(3) = p(4) =P(5) = p(6) = 1/6.This die is rolled 4 times in row and the 4 outcomes are
Assume we have available a fair die with outcomes, 1, 2, 3, 4, 5, and 6 and with probability mass function p(1) = P(2) = p(3) = p(4) =P(5) = p(6) = 1/6.This die is rolled 4 times in row and the 4 outcomes are
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:Assume we have available a fair die with
outcomes, 1, 2, 3, 4, 5, and 6 and with
probability mass function p(1) = P(2) = p(3)
= p(4) =P(5) = p(6) = 1/6.This die is rolled 4
times in row and the 4 outcomes are
added. Compute the probability mass
function of this sum, X = X1+X2+X3+X4. Plot
this probability mass function using either
the hist, bar, barh function. This die is rolled
16 times in row and the 16 outcomes are
added. Compute the probability mass
function of this sum, X =X1 + X2 + + X16-
Plot this probability mass function using
either the hist, bar, barh function
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