Assume the random variable x is normally distributed with mean = 90 and standard deviation o=5. Find the indicated probability. P(x<83) P(x<83)= 0.0808 (Round to four decimal places as needed.)
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Q: Assume the random variable x is normally distributed with mean μ = 85 and standard deviation a=4.…
A: The random variable x is normally distributed. Mean = μ = 85 Standard deviation = σ = 4
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Q: Assume the random variable x is normally distributed with mean u= 80 and standard deviation o = 5.…
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Q: Assume the random variable x is normally distributed with mean μ=82 and standard deviation σ=5. Find…
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Q: Assume the random variable x is normally distributed with mean u= 82 and standard deviation o =4.…
A: The random variable X follows normal distribution. The population mean is 82. The population…
Q: Assume the random variable x is normally distributed with mean μ = 80 and standard deviation o=4.…
A: Given that Mean = 80 , Standard deviation = 4
Q: Assume the random variable x is normally distributed with mean μ = 85 and standard deviation o=5.…
A: The population mean is 85 and the population standard deviation is .
Q: Assume the random variable x is normally distributed with mean μ = 80 and standard deviation o=4.…
A: givendata normal distributionμ = 80σ = 4P(68<x<77) = ?
Q: P(65<x<74) P(65<x<74)= (Round to four decimal places as needed.)
A: X~N( μ , ?)μ=80 , ?=5Z-score =( x - μ )/?
Q: Assume the random variable x is normally distributed with mean = 90 and standard deviation a=5. Find…
A: The following information has been given: μ=90σ=5 We need to compute Px<83.
Q: Assume the random variable x is normally distributed with meanu=81 and standard deviation o = 4.…
A:
Q: Assume the random variable x is normally distributed with mean μ = 85 and standard deviation o=4.…
A: Given that the data is normally distributed with mean 85 and standard deviation 4.Mean () =…
Q: Assume the random variable x is normally distributed with mean u= 90 and standard deviation o = 4.…
A: Solution-: Let, X= be the random variable Given: μ=90,σ=4 ∴X→ N(μ=90,σ2=42) We find, P[X<86]=?
Q: Assume the random variable x is normally distributed with mean = 50 and standard deviation o=7. Find…
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Q: Assume the random variable x is normally distributed with mean u = 90 and standard deviation o = 4.…
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Q: Assume the random variable x is normally distributed with mean μ=85 and standard deviation σ=4. Find…
A: Answer:- Assume the random variable x is normally distributed with mean μ=85 and standard deviation…
Q: Assume the random variable x is normally distributed with mean μ = 85 and standard deviation o=4.…
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Q: Assume the random variable x is normally distributed with mean u = 85 and standard deviation o = 5.…
A: Given: μ=85σ=5 The z-score is given by, z=X-μσ
Q: Assume the random variable x is normally distributed with mean μ = 82 and standard deviation σ = 5.…
A: X~N(μ=82,σ=5) and P(X<78)=?
Q: Assume the random variable x is normally distributed with mean µ = 88 and standard deviation o = 4.…
A: Mean = 88Standard deviation = 4
Q: Assume the random variable x is normally distributed with mean μ = 50 and standard deviation o = 7.…
A:
Q: Assume the random variable x is normally distributed with mean μ=81 and standard deviation σ=5. Find…
A: Mean(μ)=81standard deviation(σ)=5
Q: Assume the random variable x is normally distributed with mean μ = 84 and standard deviation o=5.…
A: From the provided information,Mean (µ) = 84Standard deviation (σ) = 5
Q: Assume the random variable x is normally distributed with mean u= 82 and standard deviation o = 5.…
A:
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Q: Assume the random variable x is normally distributed with mean μ = 50 and standard deviation o=7.…
A: GivenMean(μ)=50Standard deviation(σ)=7
Q: Assume the random variable x is normally distributed with mean μ = 84 and standard deviation o= 5.…
A: Given that Mean = 84 , Standard deviation = 5
![Assume the random variable x is normally distributed with mean μ = 90 and standard deviation a=5. Find the indicated probability.
P(x <83)
P(x<83)= 0.0808 (Round to four decimal places as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5ca2ffcd-84eb-47fb-bb0a-a49dd1e69094%2F8b21795c-354a-4f33-b148-adf3b97cc045%2Fq7w8x9_processed.jpeg&w=3840&q=75)
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- Assume the random variable x is normally distributed with mean μ = 88 and standard deviation o=4. Find the indicated probability. P(76Assume the random variable X is normally distributed, with mean μ = 53 and standard deviation o=9. Find the 15th percentile. The 15th percentile is (Round to two decimal places as needed.)Assume the random variable x is normally distributed with mean μ = 50 and standard deviation a=7. Find the indicated probability. P(x > 38) P(x>38) = (Round to four decimal places as needed.) XXXXAssume the random variable x is normally distributed with mean µ = 88 and standard deviation o = 4. Find the indicated probability. P(78Assume the random variable x is normally distributed with mean μ = 88 and standard deviation o= 5. Find the indicated probability. P(x<78) P(x<78) = ... (Round to four decimal places as needed.)Assume the random variable x is normally distributed with mean µ = 87 and standard deviation o = 5. Find the indicated probability. P(70Assume the random variable x is normally distributed with mean μ=8585 and standard deviation σ=44. Find the indicated probability. P(x<77)An Assume the random variable x is normally distributed with mean p=82 and standard deviation o=4. Find the indicated probability.P(x<80)P(x<80)=(Round to four decimal places as needed.)Assume the random variable x is normally distributed with mean µ = 85 and standard deviation o = 4. Find the indicated probability. P(x<77) P(x<77) = (Round to four decimal places as needed.)Assume the random variable x is normally distributed with mean µ = 85 and standard deviation o=4. Find the indicated probability. P(x < 80) P(x <80) = (Round to four decimal places as needed.)Suppose that the weight of an newborn fawn is Uniformly distributed between 2.2 and 3.8 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. The mean of this distribution is The standard deviation is The probability that fawn will weigh exactly 2.4 kg is P(x = 2.4) = The probability that a newborn fawn will be weigh between 2.9 and 3.7 is P(2.9 < x < 3.7) = The probability that a newborn fawn will be weigh more than 2.72 is P(x > 2.72) = P(x > 2.8 | x < 3.5) = Find the 25th percentile.Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. FreemanMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman