Assume the annual day care cost per child is normally distributed with a mean of $9000 and a standard deviation of $1300. What percent of day care costs are more than $8800 annually? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. O % (Round to two decimal places as needed.)
Assume the annual day care cost per child is normally distributed with a mean of $9000 and a standard deviation of $1300. What percent of day care costs are more than $8800 annually? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. O % (Round to two decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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- [View Page 2 of the Standard Normal Distribution Table](#)
**Calculation Instructions:**
To find the percentage, use the Z-score formula:
\[ Z = \frac{(X - \mu)}{\sigma} \]
- \( X \) = $8800
- \( \mu \) (mean) = $9000
- \( \sigma \) (standard deviation) = $1300
After computing the Z-score, use the standard normal distribution table to find the corresponding percentage.
**Enter your result:**
\[ \_\_\_\_\% \] (Round to two decimal places as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9be623a7-90d5-41e9-81e6-b351e0cb0341%2Fdc3f415c-9904-4e8e-a391-12c7d0d4f4d9%2Fdn2lh6l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Understanding Annual Day Care Costs Using Normal Distribution**
Assume that the annual day care cost per child is normally distributed. The mean cost is $9000, and the standard deviation is $1300. We aim to determine what percentage of day care costs are more than $8800 annually.
To assist in this calculation, refer to the standard normal distribution tables linked below:
- [View Page 1 of the Standard Normal Distribution Table](#)
- [View Page 2 of the Standard Normal Distribution Table](#)
**Calculation Instructions:**
To find the percentage, use the Z-score formula:
\[ Z = \frac{(X - \mu)}{\sigma} \]
- \( X \) = $8800
- \( \mu \) (mean) = $9000
- \( \sigma \) (standard deviation) = $1300
After computing the Z-score, use the standard normal distribution table to find the corresponding percentage.
**Enter your result:**
\[ \_\_\_\_\% \] (Round to two decimal places as needed.)
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