assume that you are studying a cart and mass system. given m1 = 20kg and m2 = 30 kg and theta = 35 degrees, find the acceleration, a, and the tension, T, of the system.
assume that you are studying a cart and mass system. given m1 = 20kg and m2 = 30 kg and theta = 35 degrees, find the acceleration, a, and the tension, T, of the system.
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18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
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assume that you are studying a cart and mass system. given m1 = 20kg and m2 = 30 kg and theta = 35 degrees, find the acceleration, a, and the tension, T, of the system.
![rection of a force (tension) without changing its magnitude.
can be considered part of the same system. As long as the
pulley, the masses in the system have the same speed and
analyze a system with a pulley can be confusing, because
e pulley.
ystem of two masses connected by a string over a pulley.
m1,
own
fric-
ngs
and
phill
, or
m₂).
mi
ons.
the
roll
Sec-
be
of the pulley is negligible. If the mass of the pulley was
ergy from the cart-mass system, which would reduce the
efore, there would have to be some force associated with
rotational motion). While the pulley obviously has some
ging mass, so it is safe to assume the mass of the pulley is
pulley without slipping. If it does not, there will be kinetic
educe the acceleration of the system. There is in fact static
he string from slipping! However, this static friction does
ce to the string that changes the direction of the tension in
tude of the tension.
Figure 1: Cart and hanging mass.
e the hanging mass, let us consider all of the forces acting
wton's Second Law of Motion to both. Recall Newton's
(1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff45aa61f-c13f-4b49-82fa-07477959eb5c%2F25180fa2-ba51-4e42-bb5b-39f72fb3316c%2F0oc1bsa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:rection of a force (tension) without changing its magnitude.
can be considered part of the same system. As long as the
pulley, the masses in the system have the same speed and
analyze a system with a pulley can be confusing, because
e pulley.
ystem of two masses connected by a string over a pulley.
m1,
own
fric-
ngs
and
phill
, or
m₂).
mi
ons.
the
roll
Sec-
be
of the pulley is negligible. If the mass of the pulley was
ergy from the cart-mass system, which would reduce the
efore, there would have to be some force associated with
rotational motion). While the pulley obviously has some
ging mass, so it is safe to assume the mass of the pulley is
pulley without slipping. If it does not, there will be kinetic
educe the acceleration of the system. There is in fact static
he string from slipping! However, this static friction does
ce to the string that changes the direction of the tension in
tude of the tension.
Figure 1: Cart and hanging mass.
e the hanging mass, let us consider all of the forces acting
wton's Second Law of Motion to both. Recall Newton's
(1)
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