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assume that you are studying a cart and mass system. given m1 = 20kg and m2 = 30 kg and theta = 35 degrees, find the acceleration, a, and the tension, T, of the system.

assume that you are studying a cart and mass system. given m1 = 20kg and m2 = 30 kg and theta = 35 degrees, find the acceleration, a, and the tension, T, of the system.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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assume that you are studying a cart and mass system. given m1 = 20kg and m2 = 30 kg and theta = 35 degrees, find the acceleration, a, and the tension, T, of the system.

rection of a force (tension) without changing its magnitude. can be considered part of the same system. As long as the pulley, the masses in the system have the same speed and analyze a system with a pulley can be confusing, because e pulley. ystem of two masses connected by a string over a pulley. m1, own fric- ngs and phill , or m₂). mi ons. the roll Sec- be of the pulley is negligible. If the mass of the pulley was ergy from the cart-mass system, which would reduce the efore, there would have to be some force associated with rotational motion). While the pulley obviously has some ging mass, so it is safe to assume the mass of the pulley is pulley without slipping. If it does not, there will be kinetic educe the acceleration of the system. There is in fact static he string from slipping! However, this static friction does ce to the string that changes the direction of the tension in tude of the tension. Figure 1: Cart and hanging mass. e the hanging mass, let us consider all of the forces acting wton's Second Law of Motion to both. Recall Newton's (1)
Transcribed Image Text:rection of a force (tension) without changing its magnitude. can be considered part of the same system. As long as the pulley, the masses in the system have the same speed and analyze a system with a pulley can be confusing, because e pulley. ystem of two masses connected by a string over a pulley. m1, own fric- ngs and phill , or m₂). mi ons. the roll Sec- be of the pulley is negligible. If the mass of the pulley was ergy from the cart-mass system, which would reduce the efore, there would have to be some force associated with rotational motion). While the pulley obviously has some ging mass, so it is safe to assume the mass of the pulley is pulley without slipping. If it does not, there will be kinetic educe the acceleration of the system. There is in fact static he string from slipping! However, this static friction does ce to the string that changes the direction of the tension in tude of the tension. Figure 1: Cart and hanging mass. e the hanging mass, let us consider all of the forces acting wton's Second Law of Motion to both. Recall Newton's (1)
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