Assume that we need to transmit a color image containing 12 million pixels, and each pixel is encoded using 2 bytes. How long will it take to transmit this image on 10 Mbps Ethernet link? Enter your answer in seconds as a decimal value. Do not enter alphabetical characters, symbols or spaces. seconds If we want to transmit this image over a computer network in no more than 0.1 seconds. What is the minimal necessary line speed to meet this goal? Enter your answer in Gbps as a decimal value. Do not enter alphabetical characters, symbols or spaces. Gbps

Assume that we need to transmit a color image containing 12 million pixels, and each pixel is encoded using 2 bytes. How long will it take to transmit this image on 10 Mbps Ethernet link? Enter your answer in seconds as a decimal value. Do not enter alphabetical characters, symbols or spaces. seconds If we want to transmit this image over a computer network in no more than 0.1 seconds. What is the minimal necessary line speed to meet this goal? Enter your answer in Gbps as a decimal value. Do not enter alphabetical characters, symbols or spaces. Gbps

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Dear Writer could oyu please kindly explin why i get this soltuion and it is different that your solution? The transmission time of a frame can be calculated as follows: Propagation delay (Tp) = distance/speed = 5km / 200000 km/s = 0.025ms Transmission time (Tt) = frame size/bandwidth = 10000 * 8bits / (1Mbps * 10 ^ 6) = 0.008sec = 8ms Total time for transmission = 2 * Tp + Tt(since the frame has to travel from A to D and then D to A) = 2 * 0.025ms + 8ms = 0.05ms + 8ms = 8.05ms The transmission time of the frame from A to D is 8.05 ms. b) To calculate the efficiency of the CSMA/CD protocol in this LAN, we can use the formula: Efficiency = (1 / (1 + 5tprop / tframe)) tprop is the propagation delay tframe is the time it takes to transmit a frame. To calculate tprop, we need to determine the time it takes for a signal to propagate through the 5 Km distance between Station A and Station D. The speed of propagation is 200,000 Km/sec The propagation delay is: tprop = distance /…
Calculate the total number of bits used in downloading a 50 MB video file. Also calculate the time (in minutes) it takes to download the same video file, if the download link is a telephone line with 9600 baud rate. Assume 8 - bits of data per character, 1 start bit, 1 - stop bit, and 1 parity bit.
The figure below illustrates an asynchronous transmission in the form of short blocks. Each data bit is of 9.06 ms duration, start bit duration is 0.04ms more than a data bit duration, and each stop bit duration is double the duration of a start bit . Determine the bit rate and baud rate of the transmission. Data Bits Stop Bits Start Bit 1 101 0 10 010 1 Line is quiet! Direction of Data Data: 0100 1010
O Calculate the total number of bits used in downloading a 50 MB video file. Also calculate the time (in minutes) it takes to download the same video file, if the download link is a telephone line with 9600 baud rate. Assume 8 - bits of data per character, 1 – start bit, 1 - stop bit, and 1 parity bit. -
its 7-bit ASCII codeword, A multilevel PAM waveform with M 256 levels is used. If you want to transmit 1400 characters/s, where each character is represented by 1- What is the Baud Rate? 2- What is the effective transmitted Bit Rate?
Using Shannon’s noisy theorem, what bandwidth is necessary to support a 1 Gbps, assuming a signal-to-noise ratio of 40 decibels? Suppose you want to achieve a bit rate of 15 Gbps using a maximum bandwidth of 900 MHz. What is the minimum allowable signal-to-noise ratio in decibels?
A common measure of transmission digital data is the baud rate, defined as thenumber of bits transmitted per second. Generally transmission is accomplished inpackets consisting of a start bit, a byte (8 bits) of information , and a stop bit. Usingthese facts, answer the following.How many minutes would it takes to transmit a 1024 x 1024 image with 256 intenistylevels using a 56K baud modem.
What is the delay of sending a data file from a source station to a destination station? Suppose that the length of the data file is 2 Mbytes and the bandwidth of the channel is 1600 bps, and the network link between the sender and receiver is 20000 Km and the speed of the light inside the link is 2x108 meters/second? Assume that the delay is composed of only transmission time and propagation time.
An analog signal having frequency as 6,70 KHz is digitized and stored in a file. If the total time of the signal is 24 min and the file size is 3,32 Mbit , which answer is correct? O a. Bit = 6 bits Data Rate = 40,2 Kbps O b. Bit = 8 bits Data Rate = 107,2 Kbps O c. Bit = 3 bits Data Rate = 221,5 Kbps O d. Bit = 7 bits Data Rate = 93,8 Kbps O e. Bit = 7 bits Data Rate = 80,4 Kbps
Computer A uses the Go-back-N ARQ protocol to send a 110 Mbytes file to computer B with a window size of 15. Given each frame carries 100K bytes data. How long does it take to send the whole file (the total time taken from A sending the first bit of the file until A receiving the last acknowledgment)? Given that the transmission rate of the link is 500 Mbps and the propagation time between A and B is 15ms. Assume no data or control frame is lost or damaged and ignore the overhead due to header and trailer.
Four channels, two with a bit rate of 120kbps and two with a bit rate of 880kbps, are to be multiplexed using multiple-slot TDM with no synchronization bits.Answer the following questions: a. What is the size of a frame in bits? b. What is the frame rate? c. What is the duration of a frame? d. What is the data rate?
Question Three Huffman coding assigns codes to characters such that the length of the code depends on the relative frequency or weight of the corresponding character. Thus, it is a variable-length code. If the estimated frequencies for letters match the actual frequency found in an encoded message, then the length of that message will typically be less than if a fixed-length code had been used. Due to such advantages, RadiantRay Networking Sdn Bhd uses Huffman compression technique to encode the message before transmitting over the network to its customer. Suppose the message contains the following strings "a fast runner never be afraid of dark“ How many bits may be required for encoding the message without using Huffman coding? ii. Create an Huffman table indicating the number of character bits, frequencies and the code used in transmission of the message (space is also counted as a character) i.