Assume that Vxdy P (x, y) is false and that the domalh nonempty. Which of the following must also be false? Select ALL correct answers. Note: -P means the negation of P. Grading: All or Nothing.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Question:**

Assume that ∀x∃y \( P(x, y) \) is false and that the domain of discourse is nonempty. Which of the following must also be false? Select **ALL** correct answers.

Note: ~\( P \) means the negation of \( P \).

Grading: All or Nothing:

- [ ] ∃x∀y \( P(x, y) \)
- [ ] ∀x∀y \( P(x, y) \)
- [ ] ∃x∃y \( P(x, y) \)
- [ ] ∃x∀y ~\( P(x, y) \)
- [ ] ∀x∀y ~\( P(x, y) \)
Transcribed Image Text:**Question:** Assume that ∀x∃y \( P(x, y) \) is false and that the domain of discourse is nonempty. Which of the following must also be false? Select **ALL** correct answers. Note: ~\( P \) means the negation of \( P \). Grading: All or Nothing: - [ ] ∃x∀y \( P(x, y) \) - [ ] ∀x∀y \( P(x, y) \) - [ ] ∃x∃y \( P(x, y) \) - [ ] ∃x∀y ~\( P(x, y) \) - [ ] ∀x∀y ~\( P(x, y) \)
### Big-O Notation and Asymptotic Analysis

The given mathematical expression is:

\[ \left\lfloor \frac{n}{5} \right\rfloor + 6n + 3 \]

We need to determine if this expression is \( \Theta(n) \). 

**Options:**
- True
- False

The notation \( \Theta(n) \) signifies asymptotic tight bound, meaning that the function grows linearly with \( n \).

### Detailed Analysis:

1. **Floor Function \(\left\lfloor \frac{n}{5} \right\rfloor\):**
   - The floor function returns the greatest integer less than or equal to \( \frac{n}{5} \).
   - This component grows linearly with \( n \) since \( \frac{n}{5} \) is directly proportional to \( n \).

2. **Linear Term \( 6n \):**
   - This term clearly grows linearly with \( n \).

3. **Constant Term \( + 3 \):**
   - This term is constant and does not change with \( n \).

### Conclusion:
Combining all the parts together:
\[ \left\lfloor \frac{n}{5} \right\rfloor + 6n + 3 \]
- Dominated by the linear terms \( \left\lfloor \frac{n}{5} \right\rfloor \) and \( 6n \).
- The constant term \( + 3 \) does not affect the overall asymptotic behavior.

Thus, the given expression indeed grows linearly with \( n \), so it is \( \Theta(n) \).

Therefore, the correct answer is:

- True
Transcribed Image Text:### Big-O Notation and Asymptotic Analysis The given mathematical expression is: \[ \left\lfloor \frac{n}{5} \right\rfloor + 6n + 3 \] We need to determine if this expression is \( \Theta(n) \). **Options:** - True - False The notation \( \Theta(n) \) signifies asymptotic tight bound, meaning that the function grows linearly with \( n \). ### Detailed Analysis: 1. **Floor Function \(\left\lfloor \frac{n}{5} \right\rfloor\):** - The floor function returns the greatest integer less than or equal to \( \frac{n}{5} \). - This component grows linearly with \( n \) since \( \frac{n}{5} \) is directly proportional to \( n \). 2. **Linear Term \( 6n \):** - This term clearly grows linearly with \( n \). 3. **Constant Term \( + 3 \):** - This term is constant and does not change with \( n \). ### Conclusion: Combining all the parts together: \[ \left\lfloor \frac{n}{5} \right\rfloor + 6n + 3 \] - Dominated by the linear terms \( \left\lfloor \frac{n}{5} \right\rfloor \) and \( 6n \). - The constant term \( + 3 \) does not affect the overall asymptotic behavior. Thus, the given expression indeed grows linearly with \( n \), so it is \( \Theta(n) \). Therefore, the correct answer is: - True
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