assume that the voltage drop across the resistor ER is 78 v the voltage drop across the capacitor EC is 104 v and the circuit has a total impedance z of 20 ohms the frequency of the ac voltage is 60 hz find the missing values.

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assume that the voltage drop across the resistor ER is 78 v the voltage drop across the capacitor EC is 104 v and the circuit has a total impedance z of 20 ohms the frequency of the ac voltage is 60 hz find the missing values.

### Problem Statement
Assume that the circuit shown in Figure 18-1 is connected to a 60-Hz line and has a total current flow of 34.553 A. The inductor has an inductance of 0.02122 H, and the resistor has a resistance of 14 Ω.

### Table and Formulas
Below is the data presented for calculating specific electrical properties of the circuit:

- **Total Voltage (E_T):** ______
- **Voltage across Resistor (E_R):** ______
- **Voltage across Inductor (E_L):** ______
- **Total Current (I_T):** 34.553 A
- **Current through Resistor (I_R):** ______
- **Current through Inductor (I_L):** ______
- **Total Impedance (Z):** ______
- **Resistance (R):** 14 Ω
- **Inductive Reactance (X_L):** ______
- **Apparent Power (VA):** ______
- **Real Power (P):** ______
- **Reactive Power (VARs):** ______
- **Power Factor (PF):** ______
- **Phase Angle (∠θ):** ______
- **Inductance (L):** 0.02122 H

### Explanation
You need to calculate:

1. **Inductive Reactance (X_L):**  
   Use the formula \( X_L = 2 \pi f L \), where \( f = 60 \) Hz, and \( L = 0.02122 \) H.

2. **Total Impedance (Z):**  
   Use the formula \( Z = \sqrt{R^2 + X_L^2} \).

3. **Voltage and Power Calculations:**  
   - Total Voltage (\( E_T \)): Use \( E_T = I_T \times Z \).
   - Voltage across R (\( E_R \)): Use \( E_R = I_T \times R \).
   - Voltage across L (\( E_L \)): Use \( E_L = I_T \times X_L \).
   - Apparent Power (VA): Use \( VA = E_T \times I_T \).
   - Real Power (P): Use \( P = I_T^2 \times R \).
   - Reactive Power (VARs): Use \( VARs = I_T^2 \times X_L
Transcribed Image Text:### Problem Statement Assume that the circuit shown in Figure 18-1 is connected to a 60-Hz line and has a total current flow of 34.553 A. The inductor has an inductance of 0.02122 H, and the resistor has a resistance of 14 Ω. ### Table and Formulas Below is the data presented for calculating specific electrical properties of the circuit: - **Total Voltage (E_T):** ______ - **Voltage across Resistor (E_R):** ______ - **Voltage across Inductor (E_L):** ______ - **Total Current (I_T):** 34.553 A - **Current through Resistor (I_R):** ______ - **Current through Inductor (I_L):** ______ - **Total Impedance (Z):** ______ - **Resistance (R):** 14 Ω - **Inductive Reactance (X_L):** ______ - **Apparent Power (VA):** ______ - **Real Power (P):** ______ - **Reactive Power (VARs):** ______ - **Power Factor (PF):** ______ - **Phase Angle (∠θ):** ______ - **Inductance (L):** 0.02122 H ### Explanation You need to calculate: 1. **Inductive Reactance (X_L):** Use the formula \( X_L = 2 \pi f L \), where \( f = 60 \) Hz, and \( L = 0.02122 \) H. 2. **Total Impedance (Z):** Use the formula \( Z = \sqrt{R^2 + X_L^2} \). 3. **Voltage and Power Calculations:** - Total Voltage (\( E_T \)): Use \( E_T = I_T \times Z \). - Voltage across R (\( E_R \)): Use \( E_R = I_T \times R \). - Voltage across L (\( E_L \)): Use \( E_L = I_T \times X_L \). - Apparent Power (VA): Use \( VA = E_T \times I_T \). - Real Power (P): Use \( P = I_T^2 \times R \). - Reactive Power (VARs): Use \( VARs = I_T^2 \times X_L
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