Assume that the samples were actually only 100 in each case, calculate the relevant test statistic for the test in part 4 above. Estimate the þ-value. Would you Reject H,? 6. 1 P-value: Alternative Hypothesis is 69.5% or 0.695 The corresponding probability based on the z-table is 0.5. Therefore, the p-value is 1 - 0.5 = 0.5 Since p-value is z significance level, we do hot reject H. ^ this doesn't account for the sample of 100 im not sure how to do it
Assume that the samples were actually only 100 in each case, calculate the relevant test statistic for the test in part 4 above. Estimate the þ-value. Would you Reject H,? 6. 1 P-value: Alternative Hypothesis is 69.5% or 0.695 The corresponding probability based on the z-table is 0.5. Therefore, the p-value is 1 - 0.5 = 0.5 Since p-value is z significance level, we do hot reject H. ^ this doesn't account for the sample of 100 im not sure how to do it
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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100%
hey for that table we were supposed to answer this questions. its in the image 2. for that image there is a question which is question 6. how would you do that question please.
Transcribed Image Text:Table 1. Prevalence of and Percentage Change in 12-Month Alcohol Use by Sociodemographic Characteristics,
2001-2002 and 2012-2013
% (95% CI)
NESARC 2001-2002
NESARC-III 2012-2013
Sociodemographic Characteristic
(n = 43 093)
(n = 36 309)a
% Change
Total
65.4 (64.3-66.6)
72.7 (71.4-73.9)
11.2
Sex
Men
71.8 (70.6-73.0)
76.7 (75.5-77.9)
6.8
Women
59.6 (58.0-61.1)
69.0 (67.5-70.5)
15.8
Race/ethnicity
White
69.5 (68.2-70.8)
75.3 (73.7-76.9)
8.3
Black
53.2 (51.6-54.9)
66.1 (63.8-68.3)
24.2
Native American
58.2 (53.0-63.4)
73.9 (69.1-78.1)
27.0
Asian or Pacific Islander
48.4 (44.3-52.5)
62.5 (59.4-65.5)
29.1
Hispanic
59.9 (58.1-61.7)
70.2 (68.8-71.7)
17.2
Age, y
18-29
73.1 (71.5-74.7)
80.1 (78.8-81.3)
9.6
30-44
71.9 (70.4-73.4)
79.5 (78.1-80.8)
10.6
45-64
64.3 (62.9-65.7)
71.9 (70.3-73.5)
11.8
265
45.1 (43.4-46.8)
55.2 (52.8-57.6)
22.4
Marital status
Married or cohabiting
66.3 (65.0-67.6)
73.1 (71.6-74.5)
10.3
Widowed, divorced, or separated
56.8 (55.3-58.3)
67.2 (65.4-68.9)
18.3
Never married
70.1 (68.5-71.7)
76.6 (75.1-78.0)
9.3
Educational level
Less than high school
46.4 (44.8-47.9)
55.8 (53.5-58.1)
20.3
High school
60.9 (59.5-62.3)
68.0 (66.5-69.5)
11.7
Some college or higher
73.3 (72.1-74.5)
78.3 (77.1-79.5)
6.8
Family income, $
0-19 999
52.4 (51.1-53.6)
64.1 (62.2-65.9)
22.3
20 000-34 999
61.0 (59.5-62.4)
68.5 (66.8-70.1)
12.3
35 000-69 999
68.1 (66.7-69.4)
73.4 (71.8-74.9)
7.8
270000
78.4 (76.8-80.0)
81.0 (79.5-82.4)
3.3
Poverty threshold, %
<100
52.1 (50.4-53.9)
64.3 (62.5-66.0)
23.4
100-200
55.2 (53.8-56.6)
66.4 (64.4-68.3)
20.3
>200
71.3 (70.0-72.5)
77.8 (76.5-79.0)
9.1
Urbanicity
Urban
67.2 (65.8-68.5)
74.0 (72.9-75.1)
10.1
Rural
58.4 (56.5-60.2)
67.9 (64.8-70.9)
16.3
Region
Northeast
70.9 (67.2-74.4)
77.1 (75.3-78.9)
8.7
Midwest
69.9 (68.4-71.4)
76.5 (74.5-78.5)
9.4
South
59.0 (57.2-60.7)
68.2 (66.0-70.4)
15.6
West
66.1 (63.5-68.7)
72.9 (69.8-75.7)
10.3
Transcribed Image Text:What are the null and alternative
hypotheses to test if the proportion of
White Americans with 12 month
Alcohol use is different in 2012
4
1
Ho:p=
0:p = 69.5
H.
a :p > 69.5
compared to 2000?
The table says there is an 8% change Increase/ original number x 100 =
n the proportion for White Americans. þroportion
Demonstrate how this was calculated.
1
(75.3-69.5)/ 69.5 x 100 = 8.3%
Assume that the samples were
actually only 100 in each case,
calculate the relevant test statistic for
the test in part 4 above. Estimate the
þ-value. Would you Reject H,?
1
P-value:
Alternative Hypothesis is 69.5% or 0.695
The corresponding probability based on the
z-table is 0.5.
Therefore, the p-value is 1 - 0.5 = 0.5
Since p-value is > significance level, we do
hot reject H.
^ this doesn't account for the sample of
100 im not sure how to do it
LO
CO
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