hey for that table we were supposed to answer this questions. its in the image 2. for that image there is a question which is question 6. how would you do that question please. Table 1. Prevalence of and Percentage Change in 12-Month Alcohol Use by Sociodemographic Characteristics,2001-2002 and 2012-2013% (95% CI)NESARC 2001-2002NESARC-III 2012-2013Sociodemographic Characteristic(n = 43 093)(n = 36 309)a% ChangeTotal65.4 (64.3-66.6)72.7 (71.4-73.9)11.2SexMen71.8 (70.6-73.0)76.7 (75.5-77.9)6.8Women59.6 (58.0-61.1)69.0 (67.5-70.5)15.8Race/ethnicityWhite69.5 (68.2-70.8)75.3 (73.7-76.9)8.3Black53.2 (51.6-54.9)66.1 (63.8-68.3)24.2Native American58.2 (53.0-63.4)73.9 (69.1-78.1)27.0Asian or Pacific Islander48.4 (44.3-52.5)62.5 (59.4-65.5)29.1Hispanic59.9 (58.1-61.7)70.2 (68.8-71.7)17.2Age, y18-2973.1 (71.5-74.7)80.1 (78.8-81.3)9.630-4471.9 (70.4-73.4)79.5 (78.1-80.8)10.645-6464.3 (62.9-65.7)71.9 (70.3-73.5)11.826545.1 (43.4-46.8)55.2 (52.8-57.6)22.4Marital statusMarried or cohabiting66.3 (65.0-67.6)73.1 (71.6-74.5)10.3Widowed, divorced, or separated56.8 (55.3-58.3)67.2 (65.4-68.9)18.3Never married70.1 (68.5-71.7)76.6 (75.1-78.0)9.3Educational levelLess than high school46.4 (44.8-47.9)55.8 (53.5-58.1)20.3High school60.9 (59.5-62.3)68.0 (66.5-69.5)11.7Some college or higher73.3 (72.1-74.5)78.3 (77.1-79.5)6.8Family income, $0-19 99952.4 (51.1-53.6)64.1 (62.2-65.9)22.320 000-34 99961.0 (59.5-62.4)68.5 (66.8-70.1)12.335 000-69 99968.1 (66.7-69.4)73.4 (71.8-74.9)7.827000078.4 (76.8-80.0)81.0 (79.5-82.4)3.3Poverty threshold, %<10052.1 (50.4-53.9)64.3 (62.5-66.0)23.4100-20055.2 (53.8-56.6)66.4 (64.4-68.3)20.3>20071.3 (70.0-72.5)77.8 (76.5-79.0)9.1UrbanicityUrban67.2 (65.8-68.5)74.0 (72.9-75.1)10.1Rural58.4 (56.5-60.2)67.9 (64.8-70.9)16.3RegionNortheast70.9 (67.2-74.4)77.1 (75.3-78.9)8.7Midwest69.9 (68.4-71.4)76.5 (74.5-78.5)9.4South59.0 (57.2-60.7)68.2 (66.0-70.4)15.6West66.1 (63.5-68.7)72.9 (69.8-75.7)10.3 What are the null and alternativehypotheses to test if the proportion ofWhite Americans with 12 monthAlcohol use is different in 201241Ho:p=0:p = 69.5H.a :p > 69.5compared to 2000?The table says there is an 8% change Increase/ original number x 100 =n the proportion for White Americans. þroportionDemonstrate how this was calculated.1(75.3-69.5)/ 69.5 x 100 = 8.3%Assume that the samples wereactually only 100 in each case,calculate the relevant test statistic forthe test in part 4 above. Estimate theþ-value. Would you Reject H,?1P-value:Alternative Hypothesis is 69.5% or 0.695The corresponding probability based on thez-table is 0.5.Therefore, the p-value is 1 - 0.5 = 0.5Since p-value is > significance level, we dohot reject H.^ this doesn't account for the sample of100 im not sure how to do itLOCO

A 95% confidence interval for population proportion is given by p^±z*·SE, where SE is the standard…

Assume that the samples were actually only 100 in each case, calculate the relevant test statistic for the test in part 4 above. Estimate the þ-value. Would you Reject H,? 6. 1 P-value: Alternative Hypothesis is 69.5% or 0.695 The corresponding probability based on the z-table is 0.5. Therefore, the p-value is 1 - 0.5 = 0.5 Since p-value is z significance level, we do hot reject H. ^ this doesn't account for the sample of 100 im not sure how to do it

Assume that the samples were actually only 100 in each case, calculate the relevant test statistic for the test in part 4 above. Estimate the þ-value. Would you Reject H,? 6. 1 P-value: Alternative Hypothesis is 69.5% or 0.695 The corresponding probability based on the z-table is 0.5. Therefore, the p-value is 1 - 0.5 = 0.5 Since p-value is z significance level, we do hot reject H. ^ this doesn't account for the sample of 100 im not sure how to do it

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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