Assume that the relationship between the calories in a five-ounce serving and the % alcohol content for a sample of wines is linear. Use the % alcohol as the explanatory variable, and fit a least squares regression line. c. Find and interpret the value of the coefficient of determination. Mean Std. Dev. r Data table (Source:healthalicious.com) Calories % alcohol 122 119 121 123 129 236 10.6 10.1 10.1 8.8 11.1 15.2 Table of summary statistics Calories 141.67 46.34 0.95 % alcohol 11.03 2.32

Q: If SSR=36 and SSE=4, determine SST and then com-pute the coefficient of determination, r2, and…

A: Given that SSR=36 and SSE=4 We have to find SST = ? And  r2 = ?

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Q: What to do if coefficient of determination, R2, is not close to 1 or not high enough?

A: Coefficient of Determination R2 = SSRSST=Sum of squared regressionTotal variation=∑yi^-y¯2∑yi-y¯2…

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A: if SSE=45  and   SSR=5, Compute the coefficient of determination(r2)=?

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A: The correlation coefficient is given by r = 0.99

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Q: Find the coefficient of determination if SSE = 50 and SSR = 90.

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Q: What is the interpretation of the coefficient of multiple determinatio

A: What is the interpretation of the coefficient of multiple determination?

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A: Answer:

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A:

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A: Calculated values :  N1 = 200  dN1/dt = 100    N2 = 400  dN2/dt = 160

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