Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -1.395°C and 0°C. P( – 1.395 < Z < 0) = |
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- Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C.A single thermometer is randomly selected and tested. Let ZZ represent the reading of this thermometer at freezing. What reading separates the highest 15.55% from the rest? That is, if P(z>c)=0.1555, find c. C= ________ CelciusA normal population has mean =μ22 and standard deviation =σ16 . Find the values that separate the middle 60% of the population from the top and bottom 20% . The values that separate the middle 60% of the population above from the top and bottom 20% are and . Enter the answers in ascending order and round to one decimal place.Suppose X has a normal distribution with a mean of 1000 and a standard deviation of 200. Find the value “a” such that Pr ( 650 < X < a) = 0.1.
- Suppose that the heart beat per minute (bpm) of adult males has a normal distribution with a mean of μ = 72.9 bpm and a standard deviation of o=11.4 bpm. Instead of using 0.05 for identifying significant values, use the criteria that a value x is significantly high if P(x or greater) ≤0.01 and a value is significantly low if P(x or less) ≤0.01. Find the pulse rates for males that separate significant pulse rates from those that are not significant. Using these criteria, is a male pulse rate of 90 beats per minute significantly high? RICHIED Find the heart rate (in bpm) separating significant values from those that are not significant. A heart rate with a bpm more than and less than are not significant, and values outside that range are considered significant.Assume that females have pulse rates that are normally distributed with a mean of μ = 74.0 beats per minute and a standard deviation of σ = 12.5 beats per minute. Complete parts (a) through (c) below. a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 80 beats per minute. The probability is 0.6844. (Round to four decimal places as needed.) b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 80 beats per minute. The probability is 0.9918. (Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? ○ A. Since the distribution is of sample means, not individuals, the distribution is a normal distribution for any sample size. ○ B. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size. ○ C. Since the mean pulse rate…Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1.If P(−b<z<b)=0.1904, find b.
- Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -2.501°C and -1.165°C.P(−2.501<Z<−1.165)Assume that females have pulse rates that are normally distributed with a mean of μ = 74.0 beats per minute and a standard deviation of σ = 12.5 beats per minute. Complete parts (a) through (c) below. a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 80 beats per minute. The probability is 0.6844. (Round to four decimal places as needed.) b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 80 beats per minute. The probability is (Round to four decimal places as needed.)Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of μ= 1.1 kg and a standard deviation of σ = 4.4 kg. Complete parts (a) through (c) below. a. If 1 male college student is randomly selected, find the probability that he gains between 0 kg and 3 kg during freshman year. The probability is 0.2658. (Round to four decimal places as needed.) b. If 9 male college students are randomly selected, find the probability that their mean weight gain during freshman year is between 0 kg and 3 kg. The probability is (Round to four decimal places as needed.)
- The contents of 37 cans of Coke have a mean of x¯¯¯=12.15x¯=12.15. Assume the contents of cans of Coke have a normal distribution with standard deviation of σ=0.13.σ=0.13. Find the value of the test statistic zz for the claim that the population mean is μ=12.μ=12.The test statistic isAssume that females have pulse rates that are normally distributed with a mean of μ=75.0 beats per minute and a standard deviation of σ = 12.5 beats per minute. Complete parts (a) through (c) below. a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 82 beats per minute. The probability is 0.7123. (Round to four decimal places as needed.) b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 82 beats per minute. The probability is 0.9974. (Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? OA. Since the mean pulse rate exceeds 30, the distribution of sample means is a normal distribution for any sample size. OB. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size. OC. Since the distribution is of…The mean score of a competency test is 77, with a standard deviation of 5. Use the empirical rule to find the percentage of scores between 72 and 82. (Assume the data set has a bell-shaped distribution.) O A. 95% O B. 50% O C. 99.7% O D. 68% Next 5:27 PM 59°F Clear A 11/23/2021 9 Type here to search Insert 々 F1 PrtSc F2 F3 F4 F5 F6 F7 F8 F9 F10 F11 F12 %23 1 2 6. Q E T Y + I/ * 00 因 44 %#3