Assume that the probability of a being born with Genetic Condition B is p = 11/60. A study looks at a random sample of 1384 volunteers. Find the most likely number of the 1384 volunteers to have Genetic Condition B. (Round answer to one decimal place.) H = Let X represent the number of volunteers (out of 1384) who have Genetic Condition B. Find the standard deviation for the probability distribution of X. (Round answer to two decimal places.) 0= Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers.

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Assume that the probability of a being born with Genetic Condition B is p = 11/60. A study looks at a
random sample of 1384 volunteers.
Find the most likely number of the 1384 volunteers to have Genetic Condition B.
(Round answer to one decimal place.)
μ =
Let X represent the number of volunteers (out of 1384) who have Genetic Condition B. Find the standard
deviation for the probability distribution of X.
(Round answer to two decimal places.)
0 =
Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+20.
Enter answer as an interval using square-brackets only with whole numbers.
usual values=
Transcribed Image Text:Assume that the probability of a being born with Genetic Condition B is p = 11/60. A study looks at a random sample of 1384 volunteers. Find the most likely number of the 1384 volunteers to have Genetic Condition B. (Round answer to one decimal place.) μ = Let X represent the number of volunteers (out of 1384) who have Genetic Condition B. Find the standard deviation for the probability distribution of X. (Round answer to two decimal places.) 0 = Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values=
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