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Assume that the permeability of oxygen in the alveoli is P=4x10-8 cms-1. The P O2 in alveolar air is 100 mmHg, while the P O2 of venous blood is 40 mmHg. The solubility of O2 is given by Henry’s Law as [O2] = 0.003 ml O2 (100 ml plasma)−1 mm Hg−1x P O2 in mmHg. Only the dissolved O2 diffuses. What is the initial rate of O2 diffusion from the aggregate alveoli to the blood? (Initial rate means to pretend that the venous P O2 is clamped at 40 mmHg.) Give the answer in mL O2 per minute. The area of the alveoli is 75 m2, and k is equal to 0.0005.

Assume that the permeability of oxygen in the alveoli is P=4x10-8 cms-1. The P O2 in alveolar air is 100 mmHg, while the P O2 of venous blood is 40 mmHg. The solubility of O2 is given by Henry’s Law as [O2] = 0.003 ml O2 (100 ml plasma)−1 mm Hg−1x P O2 in mmHg. Only the dissolved O2 diffuses. What is the initial rate of O2 diffusion from the aggregate alveoli to the blood? (Initial rate means to pretend that the venous P O2 is clamped at 40 mmHg.) Give the answer in mL O2 per minute. The area of the alveoli is 75 m2, and k is equal to 0.0005.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Assume that the permeability of oxygen in the alveoli is P=4x10-8 cms-1. The P O2 in alveolar air is 100 mmHg, while the P O2 of venous blood is 40 mmHg. The solubility of O2 is given by Henry’s Law as [O2] = 0.003 ml O2 (100 ml plasma)−1 mm Hg−1x P O2 in mmHg. Only the dissolved O2 diffuses. What is the initial rate of O2 diffusion from the aggregate alveoli to the blood? (Initial rate means to pretend that the venous P O2 is clamped at 40 mmHg.) Give the answer in mL O2 per minute. The area of the alveoli is 75 m2, and k is equal to 0.0005.
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