Assume that the matrix A is row equivalent to B. Finda basis for the row space of the matrix A.13 -414 -54 -4AВ%3D1 -5-3-3 -1-413 -41-234-60 -8-1925{(1, 3, -4, 0, 1), (2, 4, -5, 4), -4, (1, -5, 0, -3, 2),(-3, -1, 8, 3, -4)}О «1, 3, -4, 0, 1), (0, -2, 3, 4, -6), (0, 0, -8, -19,25)}{(1, 3, -4, 0, 1), (0, -2, 3, 4, -6), (О, 0, -8, -19,25), (0, 0, 0, 0, 0)}О «1, 0, о, 0), (3, -2, 0, 0), (-4, 3, -8, 0)}21

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Assume that the matrix A is row equivalent to B. Find a basis for the row space of the matrix A. 1 -4 1 4 -5 4 -4 A В %3D 1 -5 -3 -3 -1 -4 1 3 -4 1 -2 3 4 -6 -8 -19 25 {(1, 3, -4, 0, 1), (2, 4, -5, 4), -4, (1, -5, 0, -3, 2), (-3, -1, 8, 3, -4)} О {(1, 3, -4, 0, 1), (0, -2, 3, 4, -6), (0, 0, -8, -19, 25)} {(1, 3, -4, 0, 1), (0, -2, 3, 4, -6), (О, 0, -8, -19, 25), (0, 0, 0, 0, 0)} O {(1, 0, 0, 0), (3, -2, 0, 0), (-4, 3, -8, 0)} 3. 21 II

Assume that the matrix A is row equivalent to B. Find a basis for the row space of the matrix A. 1 -4 1 4 -5 4 -4 A В %3D 1 -5 -3 -3 -1 -4 1 3 -4 1 -2 3 4 -6 -8 -19 25 {(1, 3, -4, 0, 1), (2, 4, -5, 4), -4, (1, -5, 0, -3, 2), (-3, -1, 8, 3, -4)} О {(1, 3, -4, 0, 1), (0, -2, 3, 4, -6), (0, 0, -8, -19, 25)} {(1, 3, -4, 0, 1), (0, -2, 3, 4, -6), (О, 0, -8, -19, 25), (0, 0, 0, 0, 0)} O {(1, 0, 0, 0), (3, -2, 0, 0), (-4, 3, -8, 0)} 3. 21 II

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Concept explainers

Linear Algebra

In mathematics, problems can be solved by the arithmetic operators like addition, subtraction, multiplication, and division. In algebra, we represent the numbers by any letter called a variable. If these variables are of degree 1, then it is studied under linear algebra. The first-degree equations involving algebraic expressions are called linear equations. That is, if you represent it by drawing a graph you will get a straight line.

Question

Assume that the matrix A is row equivalent to B. Find
a basis for the row space of the matrix A.
1
3 -4
1
4 -5
4 -4
A
В
%3D
1 -5
-3
-3 -1
-4
1
3 -4
1
-2
3
4
-6
0 -8
-19
25
{(1, 3, -4, 0, 1), (2, 4, -5, 4), -4, (1, -5, 0, -3, 2),
(-3, -1, 8, 3, -4)}
О «1, 3, -4, 0, 1), (0, -2, 3, 4, -6), (0, 0, -8, -19,
25)}
{(1, 3, -4, 0, 1), (0, -2, 3, 4, -6), (О, 0, -8, -19,
25), (0, 0, 0, 0, 0)}
О «1, 0, о, 0), (3, -2, 0, 0), (-4, 3, -8, 0)}
21

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