Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearingcapacity for the assumptions of general and local shear failures.GENERALguit33,834 LEYHELOCALgult = 4,744 lo jetF=200,000 lbproblem 1SAND W=5%$ = 32 °G = 2.656 ftSult =D,177 dt59months =Q109e,= 0.46 ft10 ftCLAY14 fteo = 0.9Y sar= 115 pcf C = 0.05OCR =1.1C = 0.4C, = 0.2 ft :/dayROCK

Answer We are given Radius = 6ft Diameter of footing D = 12 ft Cohesion C=0 (for sand) Depth of…

Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearing capacity for the assumptions of general and local shear failures. GENERAL guit - 33 834 LbHE gult = 4,744 Ubt LOCAL F=200,000 lb problem 1 SAND W=5% * = 32 ° G = 2.65 e,= 0.4 6 ft Sult =D,177 t 6 ft 10 ft Somontho Q109 ft CLAY 14 ft C = 0.4 Y sar= 115 pcf C = 0.05 C, = 0.2 ft :/day eo= 0.9 OCR =1.1 ROCK

Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearing capacity for the assumptions of general and local shear failures. GENERAL guit - 33 834 LbHE gult = 4,744 Ubt LOCAL F=200,000 lb problem 1 SAND W=5% * = 32 ° G = 2.65 e,= 0.4 6 ft Sult =D,177 t 6 ft 10 ft Somontho Q109 ft CLAY 14 ft C = 0.4 Y sar= 115 pcf C = 0.05 C, = 0.2 ft :/day eo= 0.9 OCR =1.1 ROCK

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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