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Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearing capacity for the assumptions of general and local shear failures. GENERAL guit - 33 834 LbHE gult = 4,744 Ubt LOCAL F=200,000 lb problem 1 SAND W=5% * = 32 ° G = 2.65 e,= 0.4 6 ft Sult =D,177 t 6 ft 10 ft Somontho Q109 ft CLAY 14 ft C = 0.4 Y sar= 115 pcf C = 0.05 C, = 0.2 ft :/day eo= 0.9 OCR =1.1 ROCK

Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearing capacity for the assumptions of general and local shear failures. GENERAL guit - 33 834 LbHE gult = 4,744 Ubt LOCAL F=200,000 lb problem 1 SAND W=5% * = 32 ° G = 2.65 e,= 0.4 6 ft Sult =D,177 t 6 ft 10 ft Somontho Q109 ft CLAY 14 ft C = 0.4 Y sar= 115 pcf C = 0.05 C, = 0.2 ft :/day eo= 0.9 OCR =1.1 ROCK

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearing capacity for the assumptions of general and local shear failures. GENERAL guit 33,834 LEYHE LOCAL gult = 4,744 lo jet F=200,000 lb problem 1 SAND W=5% $ = 32 ° G = 2.65 6 ft Sult =D,177 dt 59months =Q109 e,= 0.4 6 ft 10 ft CLAY 14 ft eo = 0.9 Y sar= 115 pcf C = 0.05 OCR =1.1 C = 0.4 C, = 0.2 ft :/day ROCK
Transcribed Image Text:Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearing capacity for the assumptions of general and local shear failures. GENERAL guit 33,834 LEYHE LOCAL gult = 4,744 lo jet F=200,000 lb problem 1 SAND W=5% $ = 32 ° G = 2.65 6 ft Sult =D,177 dt 59months =Q109 e,= 0.4 6 ft 10 ft CLAY 14 ft eo = 0.9 Y sar= 115 pcf C = 0.05 OCR =1.1 C = 0.4 C, = 0.2 ft :/day ROCK
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