Can You answer part D, E and F of this part! HomeInsertPage LayoutFormulasDataReviewViewCutArial10A A-Wrap TextGeneralCopy -Paste+.0.0000+.0Conditional FormatFormatting as TableMerge & CenterCeStyFormatJ8X v fxAB.C.D.H.K373839636363636340e)Set up the Right Tailed Test, describe what the testing is meant to show and complete thebelow:4142634363Z-Critical ValueLower Bound of Confidence IntervalThis method uses the Alpha Value to create CI IntervalsEThis method uses the Z-Statistic Above to determine P-Value.Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right.1.6449446345466464Upper Bound of Confidence IntervalP-Value64644748Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null496464Нуpothesis5051645264536454649)If we lower the Confidence Level from 95% to 90%, what impact does it have on your5565conclusion on the Two Tailed and Right Tailed Test? Show all work.56576565Explain5865596565606165626563656465656566656766686669677067676869707172737475767778798081828384858687|| |皿 HomeInsertPage LayoutFormulasDataReviewViewA CutArial10A A-CopyE Wrap TextGeneralPaste關!指FormatMerge & Center+.0.00Conditional FormatCellStylesInsertFormatting as TableJ8A x v fxABF.H.1.HeightKM.Assume that the distribution of heights of young women aged 16 to 22 is approximately Normalwith mean u = 62.05 inches. A random sample of 73 female undergraduate students at aUniversity produced a sample mean height of can be derived from the adjacent chart.2.5656456576.58SHOW YOUR FORMULAS AND ALL WORK ON THIS PAGE58588.a)Using the data set, perform an analysis to determine the below. Assume the Standard9.5858Deviation for the Sample is the same as the Standard Deviation of the Population:101159MeanStandard DeviationStandard Error62.6575342512592.959068820.34633280913601415161760606161Explain the difference between the Stardard Deviation and Standard ErrorThe standard deviation measurethe amount of dispersion from the individual data while the standard errar of the mean measure how the mean of the data is likely to be from the true population mean.18611961b)sample mean is statisticaly different from Population mean of 62.05 at an 95% ConfidenceLevel. Fill out the belowUsing the Z-Test for the Mean, assume that the Null Hypothesis is trying to determine if the2061212223616262Alpha ValueZ-Statistic0.052462-1.959963985Remember to Apply the Formula25622662c)below:Set up the Two Tailed Test, describe what the testing is meant to show and complete the276262282962Z-Critical Value1.6449This method uses the Alpha Value to create CI IntervalThis method uses the Z-Statistic Above to determine P-Value.Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right.3062Lower Bound of Confidence IntervalUpper Bound of Confidence Interval0.678831623262P-Value3334356262d)Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null62Hypothesis36633763636338394063e)Set up the Right Tailed Test, describe what the testing is meant to show and complete the4163below:42634363Z-Critical Value1.6449Lower Bound of Confidence IntervalUpper Bound of Confidence IntervalP-ValueThis method uses the Alpha Value to create CI IntervalThis method uses the Z-Statistic Above to determine P-Value.Hint: Remember, if the Z-Statistic is posilive that the Chart reads left to right.446364644546478448646464Based on the Critical Value and P-Value, explain your decision to Accept or Reject the NullHypothesis495051645264Confidence LevelHypothesis Testing

Name: Can You answer part D, E and F of this part! HomeInsertPage LayoutForm
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Description: Can You answer part D, E and F of this part! HomeInsertPage LayoutFormulasDataReviewViewCutArial10A A-Wrap TextGeneralCopy -Paste+.0.0000+.0Conditional FormatFormatting as TableMerge & CenterCeStyFormatJ8X v fxAB.C.D.H.K373839636363636340e)Set up the

c) The population mean is μ=62.05 The mean and standard deviations are x=62.65753425sd=2.95906882…

Math

Statistics

Assume that the distribution of heights of young women aged 16 to 22 is approximately Nomal with mean u = 62.05 inches. A random sample of 73 female undergraduate students at a University produced a sample mean height of can be derved from the adjacent chart. SHOW YOUR FORMULAS AND ALL WORK ON THIS PAGE a) Using the data set, perfom an analysis to detemine the below. Assume the Standard Deviation for the Sample is the same as the Standard Deviation of the Population: Mean Standard Deviation Standard Eror 62.65753425 2.95906882 0.346332809 Explain the difference between the Stardard Deviation and Standard Eror The standard deviation measurethe amount of dispersion from the individual data while the standard errar of the mean measure how the mean of the data is likaly to be from the true population mean b) Using the Z-Test for the Mean, assume that the Null Hypothesis is trying to determine if the sample mean is statistically different from Population mean of 62.05 at an 95% Confidence Level. Fill out the below Alpha Value Z-Statistic 0.05 -1.959963985 Remember to Apply the Formula c) Set up the Two Tailed Test, describe what the testing is meant to show and complete the below: Z-Critical Value Lower Bound of Confidence Interval Upper Bound of Confidence Interval P-Value 1.6449 0.6788 This method uses the Alpha Value to create CI Interval This method uses the Z-Statistic Above to detemine P-Value. Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right. d) Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null Hypothesis e) Set up the Right Taled Test, describe what the testing is meant to show and complete the below: Z-Critical Value Lower Bound of Confidence Interval 1.6449 This method uses the Alpha Value to create Ci Interval This method uses the Z-Statistic Above to detemine P-Value. Hint: Remember, if the Z-Statistic is positive that the Chart reads left to right. Upper Bound of Confidence Interval P-Value Based on the Critical Value and P-Value, explain your decision to Accept or Reject the Null Hypothesis