assume that the circuit shown in figure 22-2 is connected to a 600 hz line and has a current flow through the resistor of 65.6 A and a current flow through the capacitor of 124.8 A the total impedance of the circuit is 2.17888 ohms find the missing values

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assume that the circuit shown in figure 22-2 is connected to a 600 hz line and has a current flow through the resistor of 65.6 A and a current flow through the capacitor of 124.8 A the total impedance of the circuit is 2.17888 ohms find the missing values

**Title:** Calculating Circuit Values

**Unit:** 22 Resistive-Capacitive Parallel Circuits

**Example 22-1**

---

This section provides an example of calculating circuit values in a resistive-capacitive parallel circuit setup.

**Diagram Overview:**

The diagram illustrates a parallel circuit arrangement with both resistive and capacitive components. The total circuit voltage is given as **Et 240 V**.

- **Resistive Branch (Left):**
  - **Voltage (Er):** 240 V
  - **Current (Ir):** 
  - **Resistance (R):** 30 Ω
  - **Power (P):**

- **Capacitive Branch (Right):**
  - **Voltage (Ec):** 240 V
  - **Current (Ic):** 
  - **Capacitive Reactance (Xc):** 20 Ω
  - **Reactive Power (VARs):**

**Symbols & Parameters:**

- **It:** Total current
- **Z:** Impedance
- **VA:** Apparent power
- **PF:** Power factor
- **θ:** Phase angle

The circuit is characterized by a sinusoidal waveform, indicating an AC supply.

This example helps learners understand how to break down parallel circuits into their components and calculate various electrical parameters such as impedance, current, and power factor, using given values of voltage, resistance, and reactance.
Transcribed Image Text:**Title:** Calculating Circuit Values **Unit:** 22 Resistive-Capacitive Parallel Circuits **Example 22-1** --- This section provides an example of calculating circuit values in a resistive-capacitive parallel circuit setup. **Diagram Overview:** The diagram illustrates a parallel circuit arrangement with both resistive and capacitive components. The total circuit voltage is given as **Et 240 V**. - **Resistive Branch (Left):** - **Voltage (Er):** 240 V - **Current (Ir):** - **Resistance (R):** 30 Ω - **Power (P):** - **Capacitive Branch (Right):** - **Voltage (Ec):** 240 V - **Current (Ic):** - **Capacitive Reactance (Xc):** 20 Ω - **Reactive Power (VARs):** **Symbols & Parameters:** - **It:** Total current - **Z:** Impedance - **VA:** Apparent power - **PF:** Power factor - **θ:** Phase angle The circuit is characterized by a sinusoidal waveform, indicating an AC supply. This example helps learners understand how to break down parallel circuits into their components and calculate various electrical parameters such as impedance, current, and power factor, using given values of voltage, resistance, and reactance.
**Problem 3 Explanation:**

In this problem, you are given a circuit that, as shown in Figure 22-2, is connected to a 600-Hz line. The circuit has a current flow through the resistor of 65.6 A and a current flow through the capacitor of 124.8 A. The total impedance of the circuit is 2.17888 Ω. You are tasked with finding the missing values in the table below.

**Given Values:**
- \( Z = 2.17888 \, \Omega \)
- \( I_R = 65.6 \, \text{A} \)
- \( I_C = 124.8 \, \text{A} \)

**Table to Find Missing Values:**

- \( E_T \): Total voltage
- \( I_T \): Total current
- \( VA \): Apparent power
- \( PF \): Power factor
- \( E_R \): Voltage across the resistor
- \( R \): Resistance
- \( P \): Real power
- \( \theta \): Phase angle
- \( E_C \): Voltage across the capacitor
- \( X_C \): Capacitive reactance
- \( VAR_{sc} \): Reactive power
- \( C \): Capacitance

**Instructions:**

To solve for these values, use relevant electrical engineering formulas, such as Ohm's Law, power equations, and impedance relationships for AC circuits. Consider the relationships between voltage, current, power factor, and impedance to complete the table with all necessary calculations.
Transcribed Image Text:**Problem 3 Explanation:** In this problem, you are given a circuit that, as shown in Figure 22-2, is connected to a 600-Hz line. The circuit has a current flow through the resistor of 65.6 A and a current flow through the capacitor of 124.8 A. The total impedance of the circuit is 2.17888 Ω. You are tasked with finding the missing values in the table below. **Given Values:** - \( Z = 2.17888 \, \Omega \) - \( I_R = 65.6 \, \text{A} \) - \( I_C = 124.8 \, \text{A} \) **Table to Find Missing Values:** - \( E_T \): Total voltage - \( I_T \): Total current - \( VA \): Apparent power - \( PF \): Power factor - \( E_R \): Voltage across the resistor - \( R \): Resistance - \( P \): Real power - \( \theta \): Phase angle - \( E_C \): Voltage across the capacitor - \( X_C \): Capacitive reactance - \( VAR_{sc} \): Reactive power - \( C \): Capacitance **Instructions:** To solve for these values, use relevant electrical engineering formulas, such as Ohm's Law, power equations, and impedance relationships for AC circuits. Consider the relationships between voltage, current, power factor, and impedance to complete the table with all necessary calculations.
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