Assume that RL = 1K Ohm in the loaded voltage divider shown below. Calculate the output voltage across the load resistor from point B to point C using the loaded voltage divider equation. A R1 2k Ohm A6 R2 RL 1k Ohm O 1.8 V 2 V 8V O 7.2 V

Q: Find voltage in terminal A-B. IT = 2mA - Si R₁-20 M A Ri=5Q Ge R-602 Si R₁=70 B

A: Step 1:to solve the terminal voltage. Once the current is found, the terminal voltage can be…

Q: Determine Ct for the circuit of Figure

A: The capacitor connected in parallel are added to get the equivalent capacitance and the capacitor…

Q: R1 R2 680 N 1.0 kN 10 mA R3 30 V R5 R4 270 N 270 N +

A: Equivalent resistance of the circuit Req=R1+R2+R3+R4+R5Req=680+1000+R3+270+270Req=2220+R3 Ω

Q: How would you find total Resistance. I found Ra of R7,Rload, and R8 to be 12kOhms. Rb of R6 and Ra…

A: R7, Rload and R8 are series, Ra = 2 + 4 + 6 = 12 kΩRa and R6 parallel, Rb = 12 * 6 / (12 + 6) = 4…

Q: For the potential divider shown in the figure, VIN = 10 V, R1= 10k and R2=4.7 k Calculate the output…

A: Ans

Q: what's the current l2 in mA? R₂ 4mA 6mA -4mA -6mA 4mA 10mA m R₂

A:

Q: what is the current through each component

A: It is given that:

Q: R₂=560K HE hie= 5002 hfe= 75 hoe=5μs Find: Zin, Zout, Av Vcc=50V RC= 3,5 k it out Rel=30052 Rez=5001

A: Given

Q: 2000 200 0.1V 1kQ Va 3kQ 10KQ 1kQ 2kQ Vo Vb 0.5V 5000 1000 Vx Vc 800Q 2000 = 2V

A:

Q: How did they get a gain of 10?

A: Given circuit is - Given values are -

Q: What is most nearly the total resistance between points A and B? R-20 c A-5A R-20 0 R- 15 V 12 V

A: Given

Q: Draw a full adder circuit by using two half adders.

A: full adder : A full adder is a circuit that has two AND gates, two EX-OR gates, and one OR gate. The…

Q: 6.34 ΜΑ νη - 12V R1 Μ 1 ΚΩ R5 1.5 ΚΩ R6 32.2ΚΩ

A:

Q: 15. In a series voltage divider, each IR voltage is proportional to its R

A:

Q: What will be the voltage gain for the given circuit?

A: For any amplifier circuit, the voltage gain is defined as the ratio of the output voltage to the…

Current Division Method

The generalized current divider formula is given by the following relation below,