Assume that orders are randomly selected from those included on the table. if one order is selected, find the probability of getting an order from A or an order that is accurate. Are the events of selecting an order from restaurant A and selecting an accurate order disjoint events?

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Assume that orders are randomly selected from those included on the table. if one order is selected, find the probability of getting an order from A or an order that is accurate. Are the events of selecting an order from restaurant A and selecting an accurate order disjoint events?

 

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### Drive-thru Order Accuracy Data

The following table displays the accuracy of drive-thru orders at four different restaurants. The table categorizes the orders as either accurate or not accurate:

|               | Drive-thru Restaurant A | Drive-thru Restaurant B | Drive-thru Restaurant C | Drive-thru Restaurant D |
|---------------|-------------------------|-------------------------|-------------------------|-------------------------|
| **Order Accurate**       | 326                     | 276                     | 250                     | 122                     |
| **Order Not Accurate**   | 39                      | 59                      | 31                      | 16                      |

#### Problem Statement

If one order is selected at random, find the probability of getting an accurate order.

**Step-by-Step Solution:**

1. **Total Orders Calculation:**
   - For each restaurant, sum the "Order Accurate" and "Order Not Accurate" to get the total number of orders:
     - Restaurant A: 326 (Accurate) + 39 (Not Accurate) = 365 Total Orders
     - Restaurant B: 276 (Accurate) + 59 (Not Accurate) = 335 Total Orders
     - Restaurant C: 250 (Accurate) + 31 (Not Accurate) = 281 Total Orders
     - Restaurant D: 122 (Accurate) + 16 (Not Accurate) = 138 Total Orders

2. **Accurate Order Probability Calculation:**
   - Sum all accurate orders: 326 (A) + 276 (B) + 250 (C) + 122 (D) = 974
   - Sum all total orders: 365 (A) + 335 (B) + 281 (C) + 138 (D) = 1119
   - Calculate the probability: \( P(\text{Order Accurate}) = \frac{\text{Total Accurate Orders}}{\text{Total Orders}} = \frac{974}{1119} \)

   - Divide the numbers and round to three decimal places:

     \[
     P(\text{Order Accurate}) \approx 0.871
     \]

Therefore, the probability of selecting an accurate order is approximately 0.871.

### Summary
This table and the associated calculations help understand and evaluate the accuracy of drive-thru orders across four different restaurants. By calculating the probabilities, we'll be able to estimate the likelihood of receiving an accurate order from a randomly selected drive
Transcribed Image Text:### Drive-thru Order Accuracy Data The following table displays the accuracy of drive-thru orders at four different restaurants. The table categorizes the orders as either accurate or not accurate: | | Drive-thru Restaurant A | Drive-thru Restaurant B | Drive-thru Restaurant C | Drive-thru Restaurant D | |---------------|-------------------------|-------------------------|-------------------------|-------------------------| | **Order Accurate** | 326 | 276 | 250 | 122 | | **Order Not Accurate** | 39 | 59 | 31 | 16 | #### Problem Statement If one order is selected at random, find the probability of getting an accurate order. **Step-by-Step Solution:** 1. **Total Orders Calculation:** - For each restaurant, sum the "Order Accurate" and "Order Not Accurate" to get the total number of orders: - Restaurant A: 326 (Accurate) + 39 (Not Accurate) = 365 Total Orders - Restaurant B: 276 (Accurate) + 59 (Not Accurate) = 335 Total Orders - Restaurant C: 250 (Accurate) + 31 (Not Accurate) = 281 Total Orders - Restaurant D: 122 (Accurate) + 16 (Not Accurate) = 138 Total Orders 2. **Accurate Order Probability Calculation:** - Sum all accurate orders: 326 (A) + 276 (B) + 250 (C) + 122 (D) = 974 - Sum all total orders: 365 (A) + 335 (B) + 281 (C) + 138 (D) = 1119 - Calculate the probability: \( P(\text{Order Accurate}) = \frac{\text{Total Accurate Orders}}{\text{Total Orders}} = \frac{974}{1119} \) - Divide the numbers and round to three decimal places: \[ P(\text{Order Accurate}) \approx 0.871 \] Therefore, the probability of selecting an accurate order is approximately 0.871. ### Summary This table and the associated calculations help understand and evaluate the accuracy of drive-thru orders across four different restaurants. By calculating the probabilities, we'll be able to estimate the likelihood of receiving an accurate order from a randomly selected drive
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