Assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75 probability that a pea has green pods. Assume that the offspring peas are randomly selected in groups of 10. Complete parts(a) through (c) below.a. Find the mean and the standard deviation for the numbers of peas with green pods in the groups of 10.The value of the mean is u= peas.(Type an integer or a decimal. Do not round.)The value of the standard deviation is o = peas.(Round to one decimal place as needed.)b. Use the range rule of thumb to find the values separating results that are significantly low or significantly highValues of peas or fewer are significantly low.(Round to one decimal place as needed.)Values of peas or greater are significantly high.(Round to one decimal place as needed.)c. Is a result of 3 peas with green pods a result that is significantly low? Why or why not?The resultV significantly low, because 3 peas with green pods ispeas.(Round to one decimal place as needed.)

Answered: Image /qna-images/answer/5ddcbd48-7c7e-4b49-96ae-1a5905a65cd0.jpg

Answered: Assume that hybridization experiments…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose we want to know the mean number of shurikens thrown each night by ninjas in Konoha village. Getting this information from every ninja in the village would take forever. Instead, we randomly select 20 ninjas from the ninja school that is closest to us. a. Identify the population of interest in this survey b. Describe the parameter of interest in this survey. c. Identify the sample of interest in this survey.
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PLS. Solve Quickly Applications Problems According to a Sallie Mae survey and credit bureau data, in 2008, college students carried an average of $3173 debt on their credit cards (USA TODAY, April 13, 2009). Suppose that cur- rent credit card debts for all college students have a normal distribution with a mean of $3173 and a standard deviation of $800. Find the probability that credit card debt for a randomly se- lected college student is between $2109 and $3605.
The plasticity of a polyethylene is affected by the concentration of a solution. When low concentration of the solution is used, the true mean plasticity is 55. And when high concentration is used, the mean plasticity is 62. The standard deviation of plasticity is 4 regardless of concentration of the solution. If two random samples of size 18 are taken, find the probability that Xhigh – X low 2 5. Include your solutions. O a. Probability is about 98% O b. Probability is about 7% O. NONE O d. Probability is about 93%
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Construct all random samples consisting two observations from the given data. You are asked to guess the average weight of the six watermelons by taking a random sample without replacement from the population. Watermelon A, B, C, D, E, and F has a weight (in pounds) 19,14,15,9,10 and 17 respectively.k. What is the variance of the sampling distribution of the sample means?l. What is the probability of getting 18.00 as a mean?m. What is the probability of getting 15 as a mean?n. What is the standard deviation of the sampling distribution of the sample means?o. What is the probability of getting 14.50 as a mean?p. What is the probability of getting 16.50 as a mean?
Five pulse rates are randomly selected from a set of measurements. The five pulse rates have a mean of 68.6 beats per minute. Four of the pulse rates are 74, 70, 51, and 93. a. Find the missing value. b. Suppose that you need to create a list of n values that have a specific known mean. Some of the n values can be freely selected. How many of the n values can be freely assigned before the remaining values are determined? (The result i referred to as the number of degrees of freedom.) a. The missing value is beats per minute. (Type an integer or a decimal. Do not round.) b. Select the correct choice below and fill in the answer box to complete your choice. (Type an expression using n as the variable.) OA. Of the n values, OB. Of the n values, O C. Of the n values, (...) can be freely selected because the remaining value(s) can be expressed in terms of the assigned values and the known mean. can be freely selected because the remaining value(s) can be expressed in terms of the mean,…

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