Assume that G is a Context Free Grammar as the 4-tuple (V,T,S,P) where V={S,A,B} set of non-terminal symbols, T={ab} set of terminal symbols, and S is the start symbol, and P is the set of the production rules. Select the correct statement(s). P is defined as {X→Y: such that XEV, YE(VUT)* } P is defined as {X→Y: such that XEV, YE(VUT)* } ☐ {S→ε} can not be a subset of P. ]{S→Aa|AB|bA} can be a subset of P.
Assume that G is a Context Free Grammar as the 4-tuple (V,T,S,P) where V={S,A,B} set of non-terminal symbols, T={ab} set of terminal symbols, and S is the start symbol, and P is the set of the production rules. Select the correct statement(s). P is defined as {X→Y: such that XEV, YE(VUT)* } P is defined as {X→Y: such that XEV, YE(VUT)* } ☐ {S→ε} can not be a subset of P. ]{S→Aa|AB|bA} can be a subset of P.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![Assume that G is a Context
Free Grammar as the 4-tuple
(V,T,S,P) where V={S,A,B} set of
non-terminal symbols, T={ab}
set of terminal symbols, and S
is the start symbol, and P is the
set of the production rules.
Select the correct statement(s).
P is defined as {X→Y: such
that XEV, YE(VUT)* }
P is defined as {X→Y: such
that XEV, YE(VUT)* }
☐ {S→ε} can not be a subset
of P.
]{S→Aa|AB|bA} can be a
subset of P.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F787e229a-2368-453d-a111-0058be6bb6d9%2F0208996f-340f-4a4b-bfef-7a435636fc3a%2Fdta2f8j_processed.png&w=3840&q=75)
Transcribed Image Text:Assume that G is a Context
Free Grammar as the 4-tuple
(V,T,S,P) where V={S,A,B} set of
non-terminal symbols, T={ab}
set of terminal symbols, and S
is the start symbol, and P is the
set of the production rules.
Select the correct statement(s).
P is defined as {X→Y: such
that XEV, YE(VUT)* }
P is defined as {X→Y: such
that XEV, YE(VUT)* }
☐ {S→ε} can not be a subset
of P.
]{S→Aa|AB|bA} can be a
subset of P.
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