Assume that f : (0,1) → R is continuous, and (xn), (Yn) C (0,1) are such 1, and lim f(xn) = l, lim f(yn) lim Yn L for some real numbersl< L. that lim xn %3D %3D n00 n00 n-00 Prove that for every A E R such that l < < L there exists (zn) C (0, 1) such that lim zn = 1, and lim f(zn) = .

Q: 64y2+7=32

A: 64y2+7=32

Q: 1+2x=77

A:

Q: Find A. A= (4A)-¹ = 3 2 22

A:

Q: 4w=25

A: topic - linear equation

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: 2x Ax) = %3D 2 - 1

A:

Q: 3p - p

A: Here Given that, 3p-p

Q: Q3 is incorrect.

A: data in ascending order:- 2, 12, 14, 28, 28, 30, 32, 34, 34, 34, 42, 44, 50, 52, 58, 60, 72, 78

Q: ^2 for the scor

A: to find (sum of x)2 x= 1,5,4

Q: -3w+5=23

A:

Q: Vs-+ 12²

A: To determine:

Q: -4d = -64

A: Given  -4d=-64

Q: 1+n=15

A: -1+n=15

Q: Find fre dz |2e*dx

A:

Q: S V25 – 4x²

A: For the solution follow the next step.

Q: -8 = 6+n

A:

Q: Evaluate 8r-rs when r=6 and s=5

A: 8r-rs.........A given r=6 s=5  put r and s value in A

Q: p dx. -3x (h)

A:

Q: 4a5b• V18a3b6

A: We have to find

Q: 6+197

A: Given,          6+197

Q: S A+ AMQ for M.

A: NOTE: Refresh your page if you can't see any equations. .

Q: Find

A: We know that,                         ∫1xdx=lnx+ c We need to find  ∫4xdx

Q: 2+36=38

A: Given 2+ 36 = 38  Yes the given statement is true .

Q: dx 4е2я — 8ет + 5

A: This question can be solved using the concept of special integrals.