Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 42 couples. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 42 births. The value of the mean is u = (Type an integer or a decimal. Do not round.) The value of the standard deviation is o = (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of girls or fewer are significantly low. (Round to one decimal place as needed.) Values of girls or greater are significantly high. (Round to one decimal place as needed.) c. Is the result of 35 girls a result that is significantly high? What does it suggest about the effectiveness of the method? The result v significantly high, because 35 girls is girls. A result of 35 girls would suggest that the method (Round to one decimal place as needed.)

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Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the
likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 42 couples.
Complete parts (a) through (c) below.
nents
1 of
nts
a. Find the mean and the standard deviation for the numbers of girls in groups of 42 births.
1 of
The value of the mean is u =
(Type an integer or a decimal. Do not round.)
ok
1 of
The value of the standard deviation is o =
(Round to one decimal place as needed.)
nch
1 of 1
b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high.
Values of
girls or fewer are significantly low.
1 of 2
(Round to one decimal place as needed.)
<>
er Contents
Values of
girls or greater are significantly high.
1 of 2
for Success
(Round to one decimal place as needed.)
complete
c. Is the result of 35 girls a result that is significantly high? What does it suggest about the effectiveness of the method?
imedia Library
The result
v significantly high, because 35 girls is
girls. A result of 35 girls would suggest that the method
chase Options
(Round to one decimal place as needed.)
urse Tools
scussions
Enter your answer in each of the answer boxes.
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F10
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FI
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Transcribed Image Text:ne Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 42 couples. Complete parts (a) through (c) below. nents 1 of nts a. Find the mean and the standard deviation for the numbers of girls in groups of 42 births. 1 of The value of the mean is u = (Type an integer or a decimal. Do not round.) ok 1 of The value of the standard deviation is o = (Round to one decimal place as needed.) nch 1 of 1 b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of girls or fewer are significantly low. 1 of 2 (Round to one decimal place as needed.) <> er Contents Values of girls or greater are significantly high. 1 of 2 for Success (Round to one decimal place as needed.) complete c. Is the result of 35 girls a result that is significantly high? What does it suggest about the effectiveness of the method? imedia Library The result v significantly high, because 35 girls is girls. A result of 35 girls would suggest that the method chase Options (Round to one decimal place as needed.) urse Tools scussions Enter your answer in each of the answer boxes. LIT2090 Term Pa....pdf 2,325 山T00 1428 PHOER DEC P 11 MacBook Air DII DD 吕0 888 F10 F11 F8 F9 F5 F6 F7 FI F2 F3 F4 2$4 8. %24
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