Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 23 couples. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 23 births. The value of the mean is u=. (Type an integer or a decimal. Do not round.) The value of the standard deviation is o=. (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values ofO girls or fewer are significantly low. (Round to one decimal place as needed.) Values of girls or greater are significantly high. (Round to one decimal place as needed.) c. Is the result of 19 girls a result that is significantly high? What does it suggest about the effectiveness of the method? The result (Round to one decimal place as needed.) V significantly high, because 19 girls is O girls. A result of 19 girls would suggest that the method

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Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no
effect, so the probability of a girl is 0.5. Assume that the groups consist of 23 couples. Complete parts (a) through (c) below.
a. Find the mean and the standard deviation for the numbers of girls in groups of 23 births.
The value of the mean is µ =
(Type an integer or a decimal. Do not round.)
The value of the standard deviation is o =
(Round to one decimal place as needed.)
b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high.
Values of girls or fewer are significantly low.
(Round to one decimal place as needed.)
Values of girls or greater are significantly high.
(Round to one decimal place as needed.)
c. Is the result of 19 girls a result that is significantly high? What does it suggest about the effectiveness of the method?
The result
significantly high, because 19 girls is
girls. A result of 19 girls would suggest that the method
(Round to one decimal place as needed.)
Transcribed Image Text:Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 23 couples. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 23 births. The value of the mean is µ = (Type an integer or a decimal. Do not round.) The value of the standard deviation is o = (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of girls or fewer are significantly low. (Round to one decimal place as needed.) Values of girls or greater are significantly high. (Round to one decimal place as needed.) c. Is the result of 19 girls a result that is significantly high? What does it suggest about the effectiveness of the method? The result significantly high, because 19 girls is girls. A result of 19 girls would suggest that the method (Round to one decimal place as needed.)
Expert Solution
Step 1

Given information:

Sample size, n = 23

Probability of success, that is, a baby will be a girl, p = 0.5

It is required to:

a. obtain the mean and the standard deviation for the number of girls in groups of 23 births.

b. find the values separating results that are significantly low or significantly high using the range rule of thumb.

c. determine whether the result of 19 girls is significantly high or not. Also, to figure out what it suggests about the effectiveness of the method. 

It is a case of a Binomial distribution with parameters n and p. The mean of the Binomial distribution is np and the dispersion value is npq.

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