Assume that at the average age of a population of wild turtles is normally distributed with mean age 15 years, and standard deviation 3 years. You see one of the turtles in the park. What is the age of a turtle who is at the 54 percentile? Round to two decimal places.

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**Understanding Percentiles in a Normally Distributed Population**

In this educational example, we are given a scenario about the ages of a population of wild turtles. The age distribution is normally distributed with:

- **Mean (average) age**: 15 years
- **Standard deviation**: 3 years

The problem is to determine the age of a turtle that falls at the 54th percentile.

To solve this problem, you need to understand percentiles in the context of a normal distribution:

1. **Normal Distribution**: This is a probability function that describes how the values of a variable are distributed. It's symmetric around the mean, with most values clustering around a central region and the probabilities for values tapering off equally on both sides.

2. **Percentile**: The nth percentile is a value below which n percent of data falls. For example, the 54th percentile is the value below which 54% of the observations may be found.

3. **Finding the Value at the 54th Percentile**:
   - You use the standard normal distribution or a Z-table to find a z-score corresponding to the 54th percentile.
   - Then, apply the z-score formula: 
     \[
     X = \mu + (Z \times \sigma)
     \]
     Where:
     - \(X\) is the value at the specific percentile.
     - \(\mu\) is the mean value.
     - \(Z\) is the z-score from the standard normal distribution for the given percentile.
     - \(\sigma\) is the standard deviation.

Finally, solve for \(X\) to find the age of the turtle at the 54th percentile and round your answer to two decimal places.
Transcribed Image Text:**Understanding Percentiles in a Normally Distributed Population** In this educational example, we are given a scenario about the ages of a population of wild turtles. The age distribution is normally distributed with: - **Mean (average) age**: 15 years - **Standard deviation**: 3 years The problem is to determine the age of a turtle that falls at the 54th percentile. To solve this problem, you need to understand percentiles in the context of a normal distribution: 1. **Normal Distribution**: This is a probability function that describes how the values of a variable are distributed. It's symmetric around the mean, with most values clustering around a central region and the probabilities for values tapering off equally on both sides. 2. **Percentile**: The nth percentile is a value below which n percent of data falls. For example, the 54th percentile is the value below which 54% of the observations may be found. 3. **Finding the Value at the 54th Percentile**: - You use the standard normal distribution or a Z-table to find a z-score corresponding to the 54th percentile. - Then, apply the z-score formula: \[ X = \mu + (Z \times \sigma) \] Where: - \(X\) is the value at the specific percentile. - \(\mu\) is the mean value. - \(Z\) is the z-score from the standard normal distribution for the given percentile. - \(\sigma\) is the standard deviation. Finally, solve for \(X\) to find the age of the turtle at the 54th percentile and round your answer to two decimal places.
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Let X be random variable denoting the age of a population of wild turtles. 

Given, X ~ N(15, 3)

Then We'll find the 54th percentile.

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