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Assume that an enzyme catalyzed reaction follows the scheme shown: k2 k1 ES E + P E + S k.1 Where k, = 109 M-1 sec-1, k., = 105 sec-1, k2 = 102 sec-1 and [ET] is 0.1 nM. %3D Determine Km, Vmax, and the turnover number. Km= V max= Turnover number =

Assume that an enzyme catalyzed reaction follows the scheme shown: k2 k1 ES E + P E + S k.1 Where k, = 109 M-1 sec-1, k., = 105 sec-1, k2 = 102 sec-1 and [ET] is 0.1 nM. %3D Determine Km, Vmax, and the turnover number. Km= V max= Turnover number =

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Assume that an enzyme catalyzed reaction follows the scheme shown: k1 k2 ES k.1 E + S E + P Where k, = 109 M-1 sec-1, k., = 105 sec-1, k2 = 102 sec-1 and [ET] is 0.1 nM. Determine Km, Vmax, and the turnover number. Km= V max= Turnover number =
Transcribed Image Text:Assume that an enzyme catalyzed reaction follows the scheme shown: k1 k2 ES k.1 E + S E + P Where k, = 109 M-1 sec-1, k., = 105 sec-1, k2 = 102 sec-1 and [ET] is 0.1 nM. Determine Km, Vmax, and the turnover number. Km= V max= Turnover number =
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