Assume that adults have IQ scores that are normally distributed with a mean of 101.7 and a standard deviation of 18.3. Find the probability that a randomly selected adult has an IQ greater than132.0. (Hint: Draw a graph.)The probability that a randomly selected adult from this group has an IQ greater than 132.0 is(Round to four decimal places as needed.)View an example Get more help -@22WSSaladin 25 Ext pdfXxHmmand#3SOF3EDC$4aRFSaladin9eAccess....pdf%5VTG6DBMacBook AirHPBSC A&P 2 La.....pptx&7FYCUN8JD-HEIMDPBSC A&P 2 La...pptx(9KDOO<IH)OLF10PcommandClear all>.;t{[optionCheck answer11.?IQuestion ViewerShow All1xdelete

According to the given information in this question We need to find the following probability

Answered: Assume that adults have IQ scores that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that adults have IQ score that are normally distributed with a mean of 100.4 and a standard deviation of 19.1. Find the probability that a randomly selected adult has an IQ greater than 130.7 (hint draw a graph.) the probability that a randomly selected adult from this group has an IQ greater than 130.7
The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the histogram. Complete the table. Round values to the nearest tenth as needed. Graph/chart f Midpoint x xf 70.5 Ay 30- 92.5 26 25- 114.5 136.5 20- 158.5 15- 12 Ef = Exf = 10- Find the mean of the data set. 5- X = (Round to the nearest tenth as needed.) 48.5 70.5 92.5 114.5 136.5 158.5 Complete the table. Round values to the nearest tenth as needed. Midpoint x (x-x)? (x-x)?f X-X 70.5 Print Done 92.5 114.5 136.5 158.5 (x-x)?r= ] of
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The amount of caffeine in a sample of five-ounce servings of brewed coffee is shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Click the icon to view the histogram. Graph/chart Midpoint x xt Ay 30+ 2 70.5 141 24 14 92.5 1295 25- 24 114.5 2748 20- 7 136.5 955.5 14 15- 3 158.5 475.5 10- 7 ΣΤ- 50 Exf = 5615 5- Find the mean of the data set. 48.5 70.5 92.5 114.5 136.5 158.5 x = 112.3 (Round to the nearest tenth as needed.) Complete the table. Round values to the nearest tenth as needed. Midpoint x (x-x)? (x-x)?f Print Done X-X 70.5 - 41.8 1747.2 3494.5 92.5 1295 85556.3 119787.5
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A study group takes a practice statistics exam. They find that the group has a mean score of 80 with a Standard Deviation of 5. Lily has a z-score of 1.9 and wants to know her raw score. Calculate her score. the answer is Between 89.4 and 89.6 can you please show me the work, how do I find her score?
I was wondering if these answers are correct. Explain. A study by Quadrant Information Services commissioned by Insure.com calculated auto insurance rates for each of the 50 states; and as a result, the average annual rate for the United States was $1,317. Suppose annual rates of auto insurance in the United States are normally distributed with a standard deviation of $324. According to MoneyGeek, a state minimum auto insurance policy in Florida costs an average of $1123 per year and the average cost of full coverage car insurance in Florida is $2208. What percentage of policies cost less than the Florida state minimum policy of $1123? z = (x - mu) / sigma z = (1123-1317)/324 z= -0.59876543 P-value from Z-Table: P(x<1123) = 0.27466 The answer is less than I expected. After using a z-table to determine the score it results in 27% of policies that are less than the minimum policy of 1123. What percentage of auto insurance rates would be less than $1,200? z = (x - mu) / sigma…
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Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)

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