Assume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15. Find P25, which is the IQ score separating the bottom 25% from the top 75%. Round your answer to nearest tenth. Click to view page 1 of the table. Click to view page 2 of the table. ⒸA. 91.2 OB. 91.8 OC. 90.5 O D. 89.9
Assume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15. Find P25, which is the IQ score separating the bottom 25% from the top 75%. Round your answer to nearest tenth. Click to view page 1 of the table. Click to view page 2 of the table. ⒸA. 91.2 OB. 91.8 OC. 90.5 O D. 89.9
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
Assume that adults have IQ scores that are
which is the IQ score separating the bottom 25% from the top 75%. Round your answer to nearest tenth.

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---
Explanation of the Problem:
In the context of this problem, we aim to identify the IQ score (denoted as \( P_{25} \)) that splits the bottom 25% of the population from the top 75%. This is a typical application of the percentiles in a normal distribution. To find this, we look up a Z-table or use statistical software to determine the specific IQ score corresponding to the 25th percentile of a normal distribution.
Given:
- Mean (μ) = 100
- Standard Deviation (σ) = 15
This enables us to convert between Z-scores and IQ scores using the formula:
\[ IQ = μ + Z \times σ \]
Remember to verify your answer by checking the provided choices accurately.
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Transcribed Image Text:---
### Understanding IQ Scores and the 25th Percentile
Assume that adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15.
**Problem Statement:**
Find \( P_{25} \), which is the IQ score separating the bottom 25% from the top 75%. Round your answer to the nearest tenth.
**Options:**
- A. 91.2
- B. 91.8
- C. 90.5
- D. 89.9
Click below to view the respective pages of the table necessary for this calculation:
- [Click to view page 1 of the table](#)
- [Click to view page 2 of the table](#)
**Countdown Timer:**
- Time Remaining: 03:39:16
**Navigation:**
- [Next](#)
**Additional Resources:**
- [1102Research_p_...doc](#)
- [thumbnail_IMG_...jpg](#)
- [Tables-Z-T-P-Va....pdf](#)
---
Explanation of the Problem:
In the context of this problem, we aim to identify the IQ score (denoted as \( P_{25} \)) that splits the bottom 25% of the population from the top 75%. This is a typical application of the percentiles in a normal distribution. To find this, we look up a Z-table or use statistical software to determine the specific IQ score corresponding to the 25th percentile of a normal distribution.
Given:
- Mean (μ) = 100
- Standard Deviation (σ) = 15
This enables us to convert between Z-scores and IQ scores using the formula:
\[ IQ = μ + Z \times σ \]
Remember to verify your answer by checking the provided choices accurately.
---
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